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Shalnov [3]
3 years ago
12

Simplify the following

Mathematics
2 answers:
slamgirl [31]3 years ago
5 0
The answer for the question is D. 3m
Hitman42 [59]3 years ago
4 0
3m is your answer to this question
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The world population in 2013 was about 7.125 billion. In 2003, it was about 6.357 billion. Which number represents the increase
Makovka662 [10]

Answer:

D.

7.68 × 108

Step-by-step explanation:

World population in 2013 was about 7.125 billion

In 2003 , it was about 6.357 billion

Increase = 2013 population- 2003 population

That’s 7.125 billion - 6.357 billion = 0.768 billion

A billion has 9 zeros. When you move The point one place to the right , it reduces the number of zeros by one. you now have

7.68 x 10^8

5 0
3 years ago
Solve the following equation using the distributive property
Elanso [62]

Answer:

the awnser is either a or c

Step-by-step explanation:

i hope my awnser helps

7 0
3 years ago
In a newspaper, it was reported that yearly robberies in Springfield were down 25% to 78 in 2013 from 2012. How many robberies w
anastassius [24]
There were 30% in 2012 to 2013
5 0
3 years ago
write the 2 digit numbers that matches the clues my number has tens digit that 8 more that one's digit. zero is not one my digit
Natalka [10]
The answer is 91 because the tens place has to be 8 more so in the 80's, 8 would be 8 more than 0 and 0 is not one of the digits and it's a 2 digit number so it can't go to the 100's so 91 is the best answer. I hope this helped you
7 0
3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
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