Simplify the following
2 answers:
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- Length of the hall = 12m
- wide of the hall (Breadth) = 10m
- Height of the hall = 4m
- Surface area of the walls (Four walls area)
Four walls area of the hall = 2h(l+b)
where,
- h = height
- l = length
- b = breadth
By substituting values according to the formula,
➙ 2 × 4m(12m + 10m)
➙ 8m(22m)
➠ 176m²
It's option B
<h3><u>Hence, The surface area of the walls is (B) 176m²</u></h3><h2 /><h2 />