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Mashutka [201]
2 years ago
11

Find the value of x.

Mathematics
2 answers:
Bad White [126]2 years ago
4 0

Answer:

Step-by-step explanation:

Bonsoir,

63°

castortr0y [4]2 years ago
4 0
The answer should be 63°
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Jackie's dad drives her to a friend's house at the speed 30 mph. The friend's mom drives her back using the same route at the sp
kvv77 [185]

Answer:

The distance to Jackie's friend house is 15 miles

Step-by-step explanation:

The given parameters are outlined as follows;

1) The speed with which Jackie's dad drove her to her friends house = 30 mph

2) The speed Jackie's fiend mom drove her back home on the same route = 25 mph

The time it takes Jackie's friend mom to drive her back home = 6 minutes + The time it took Jackie's dad drove her to her friends house

Let the time, in minutes, it took Jackie's dad drove her to her friends house = t

Therefore;

The time it takes Jackie's friend mom to drive her back home = 6 + t

We have that speed = Distance/Time

∴ For Jackie's friend mom, her speed of 25 mph = (The distance of Jackie's friend house)/(6 + t)

Which gives;

The distance of Jackie's friend house = 25 × (6 + t)

Similarly, for Jackie's dad, his speed of 25 mph = (The distance of Jackie's friend house)/t

Which gives;

The distance of Jackie's friend house = 30 × t

By substitution, we have;

The distance of Jackie's friend house = 25 × (6 + t) = 30 × t

By the distributive property, we have;

150 + 25·t = 30·t

150 = 30·t - 25·t = 5·t

150 = 5·t

t = 150/5 = 30 minutes

t = 30 = 0.5 Hours

Using the equation for the distance to Jackie's friend house derived with the speed of motion of Jackie's dad, we have

The distance to Jackie's friend house = 30 × t = 30 mi/h × 0.5 h = 15 mi

The distance to Jackie's friend house = 15 miles

Similarly, from the equation derived from the speed of motion of Jackie's friend mom, we have;

The distance to Jackie's friend house = 25 × (6 + t) = 25 × (6 + 30)

The distance to Jackie's friend house = 25 mph × 36 minutes

The distance to Jackie's friend house = 25 miles per hour × 0.6 hours = 15 miles

The distance to Jackie's friend house = 15 miles.

5 0
3 years ago
2 2
ExtremeBDS [4]

Answer:its 5

Step-by-step explanation:

4 0
2 years ago
Determinar la longitud de la hipotenusa del siguiente triángulo si se conocen las medidas que se indican de los demás triángulos
Zina [86]

it helps a lot in math us it won't let me do it

3 0
2 years ago
Divide<br><br> -5/9 by 5/7 :<br><br> a)-7/9<br> b)-9/7<br> c)7/9<br> d)9/7
Reil [10]

Answer:

a

Step-by-step explanation:

-5/9 ÷ 5/7

= -5/9 × 7/5

= -7/9

The answer should be a

4 0
2 years ago
From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle
Mariulka [41]

Answer:

30.11 meters ( approx )

Step-by-step explanation:

Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )

Given,

Point A is 8.20 m above level ground,

So, the height of the building = ( x + 8.20 ) meters,

Now, 1 degree = 60 minutes,

⇒ 1\text{ minute } =\frac{1}{60}\text{ degree }

20\text{ minutes }=\frac{20}{60}=\frac{1}{3}\text{ degree}

50\text{ minutes }=\frac{50}{60}=\frac{5}{6}\text{ degree}

By the below diagram,

tan ( 12^{\circ} 50') = \frac{8.20}{y}

tan(12+\frac{5}{6})^{\circ}=\frac{8.20}{y}

tan (\frac{77}{6})^{\circ}=\frac{8.20}{y}

\implies y=\frac{8.20}{tan (\frac{77}{6})^{\circ}}

Now, again by the below diagram,

tan (31^{\circ}20')=\frac{x}{y}

tan(31+\frac{1}{3})=\frac{x}{y}

\implies x=y\times tan(\frac{94}{3})=\frac{8.20}{tan (\frac{77}{6})^{\circ}}\times tan(\frac{94}{3})^{\circ}=21.9142943216\approx 21.91

Hence, the height of the building = x + 8.20 = 30.11 meters (approx)

8 0
3 years ago
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