Hey there, Lets solve this problem together.
Our first step will be to g<span>ather like terms
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Simplify 5×−2k×k to −5×2k×k
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Simplify <span><span>5×2k×k</span></span><span> to </span><span><span>10<span>k^2
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The answer is 5 because it is consecutive 3 times and it is an odd number
(-8)/(2y-8)=(5/(y+4))-7y+(8/(y^2-16))
(-4)/(y-4)=(5/(y+4))-7y+(8/(y+4)(y-4))
((-4)(y+4))/((y+4)(y-4))=((5(y-4))/(y+4)(y-4))-(7y(y+4)(y-4))/(y+4)(y-4))+(8/(y+4)(y-4))
(-4(y+4))=(5(y-4))-(7y(y+4)(y-4))+8
-4y-16=5y-20-(7y(y^2-16))+8
-4y-16=5y-20-7y^3+112y+8
-4y-16=117y-7y^3-12
-4=(121-7y^2)(y)
None of these choices would be equal to -4
Answer:
400
Step-by-step explanation:
Looking at the number 433, we have to look at the number in the tens place (in this case, 3) to determine if we will round down to 400, or up to 500.
Because the number 3 is less than 5, we will round down to 400.
Do what that person with the long explanation says it’s most likely right!!