78
16 times 72 = 1152/(192/13) = 78
In the base 6 number system, we would only use numerals
from 0 to 5. The idea of base 6 is just like the normal base 10 system, however
instead of using the numerals from 0 to 9, we use numerals from 0 to 5. And
instead of having a ones digit, a tens digit, a hundreds digit and so on, we
use a ones digit, a sixes digit, a thirty-sixes digit, and so on. Therefore in
base 6, the number 321 means 1 one plus
2 sixes plus 3 thirty-sixes, or 121. So to count until 15 for example, we would need:
Base 6
Base
10
1
1
2
2
3
3
4
4
5
5
10 (1 six plus 0
ones) 6
11 (1 six plus 1
one) 7
12 (1 six plus 2
ones) 8
13 9
14
10
15
11
20 (2 sixes plus 0
ones) 12
21 (2 sixes plus 1
one) 13
22
14
23
15
The midpoint is the average of the endpoints.
((-11+i) + (-4+4i))/2 = -15/2 +5/2i
Answer:
- (x - 3y)(3x + y)
Step-by-step explanation:
Given
(x + 2y)² - (2x - y)² ← expand both parenthesis using FOIL
= x² + 4xy + 4y² - (4x² - 4xy + y²) ← distribute
= x² + 4xy + 4y² - 4x² + 4xy - y² ← collect like terms
= - 3x² + 8xy + 3y² ← factor out - 1 from each term
= - 1(3x² - 8xy - 3y²) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the coefficient of the y² term which sum to give the coefficient of the xy- term.
product = 3 × - 3 = - 9 and sum = - 8
The factors are - 9 and + 1
Use these factors to split the xy- term
3x² - 9xy + xy - 3y² ( factor the first/second and third/fourth terms )
= 3x(x - 3y) + y(x - 3y) ← factor out (x - 3y) from each term
= (x - 3y)(3x + y)
Thus
(x + 2y)² - (2x - y)² = - (x - 3y)(3x + y)
