B: A mutation in one of G5W's parents, during gamete formation, created an X-linked dominant disease allele.
You need to analyze the sex gametes.
Boys are XY
Girls are XX
If you have an X-linked dominant disease you need only one affected X gamete to have the disease.
The mother has XX' where X' is de affected and reproduce with a healthy man XY and breed unhealthy boys, but because of the heterozygous gametes you could also have healthy ones XX and XY
Answer:
I think it is C intersexed but its not B for sure
Explanation:
At the time of this writing, the most recently available statistics pertain to 2010, at which point the World Bank reported that about 37.7 percent of the world's total land area was considered agricultural land, while approximately 10.6 percent was considered arable.
Answer:
75years
Explanation:
Let the Father's age be represented by 2x
Let the Son's age be represented by x
Five years ago;
Man's age will be = 2x - 5
Son's age will be = x - 5
If the ratio of their ages five years ago was 9:4, then;
2x - 5/x-5 = 9/4
4(2x - 5) = 9(x - 5)
8x - 20 = 9x - 45
- Collect like terms
-20 + 45 = 9x - 8x
25 = x
Hence, the son's age = 25 years
If x = 25, the father's age (2x) will be 2 × 25 = 50years
The sum of their ages will be = 25years + 50years = 75years
Bones
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