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Alina [70]
3 years ago
13

Will mark brainles if answered quickly

Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer:

A {-3, -2, -1, 0, 1, 2, 3}

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If we take the Pythagorean identity identity sin^2 x + cos^2 x = 1 then
                          <span>(cos^2 x + sin^2 x) / (cot^2 x - csc^2 x)
The numerator becomes 1 since addition order matters not.
                                                 1 / </span>(cot^2 x - csc^2 x)
If we factor the denominator out a negative
                                                1 / -(<span>csc^2 x - cot^2 x)
Consider </span><span>sin^2 x + cos^2 x = 1. Divide both sides by sin^2 x to get
                                         1 + cot^2 x = csc^2 x
Subtract both sides by cot^2 x to get 1 = csc^2 x - cot^2 x.
Replace the denominator
                                                 1 / -(1) = -1
For cos</span>^2 θ / sin^2 θ + csc θ sin θ, we use cscθ = 1/sinθ and cosθ/sinθ = cotθ so
                                = cos^2 θ / sin^2 θ + 1
                                = cot^2 θ + 1
We use 1 + cot^2 <span>θ = csc^2 </span>θ to simplify this to
                              = csc^2 θ

Answers:         -1
                          csc^2 θ
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