7/9 - 2/8 times 4/9 sum in simplest form

A square has an area of 112 cm squared what is the approximate perimeter of the square

Andreas93 [3]

Answer:

approximate perimeter is 42.32

Step-by-step explanation:

each side of a square is equal to each other

1. Find the square root of 112

$10.58^2 = 112$

2. Multiply 10.58 by 4(number of sides)

$10.58(4) = 42.32$

4 0

3 years ago

The table below represents a linear function f(x), and the equation represents a function g(x): X) -1, 0, 1 F(x) -5, -1, 3 G(x)=

fredd [130]

Answer:

(a) g(x) has a greater slope

(b) g(x) has a greater y intercept

Step-by-step explanation:

Given

$x \to -1,0,1$

$f(x) \to -5,-1,3$

$g(x) = 4x + 3$

Solving (a): Compare the slopes

Slope (m) is calculated as:

$m =\frac{y_2 - y_1}{x_2 - x_1}$

So, for f(x), we have:

$m =\frac{-1- 0}{-5- -1}$

$m =\frac{-1}{-4}$

$m =\frac{1}{4}$

For g(x), we have:

Assume $g(x) = mx + c$ then the slope is m

Compare the above to $g(x) = 4x + 3$

Then the slope of g(x) is 4

g(x) has a greater slope

Solving (b): Function with greater y intercept

Here we set $x= 0$

From the table of f(x)

$f(x) = -1$ when $x = 0$

From $g(x) = 4x + 3$

$g(0) = 4 * 0 + 3$

$g(0) = 3$

Hence:

g(x) has a greater y intercept

3 0

3 years ago

Consider f(x) = b^. Which statement(s) are true for 0 < b < 1? Check all that apply.

Elis [28]

Answer:

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

Consider f(x) = $b^{x}$ . Which statement(s) are true for 0

The domain is all real numbers.

The domain is x > 0.

The range is all real numbers.

The range is y > 0.

The graph has x-intercept 1.

The graph has a y-intercept of 1.

The function is always increasing.

The function is always decreasing.

My answer:

The domain is all real numbers.

True, the domain of a function is the complete set of possible values of the independent variable. Here, we can have unlimited values of x so we will have unlimited values of f(x)

<=> our domain (0 , +∞ )

The domain is x > 0.

Wrong, as we discussed in the aforementioned answer.

The range is all real numbers.

Wrong

The range is y > 0.

True, the range of a function is the complete set of all possible resulting values of the dependent variable (f(x), usually), after we have substituted the domain. Because this is an exponential function so:

<=> our range (0 , +∞ ) or y>0

The graph has x-intercept 1.

we can set f(x)=0 and then we can solve for x

f(x) = $b^{x}$ = 0

x is undefined so, x-intercept does not exist

The graph has a y-intercept of 1

y-intercept when x is 0, so f(x) = 1 . True.

The function is always decreasing

Because 0 < b < 1, The function is always decreasing when we increase the value of x.

So we choose A D F H

3 0

3 years ago

What should you do first to simplify the expression (43 + 9) ÷ 76 + 5

zzz [600]

Hi there!

You should always find the value inside the parenthesis first when simplifying an equation.
Tell me if you need help solving the equation!

Hope this helps!

4 0

3 years ago

Read 2 more answers

Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)

vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

Two angles are said to be supplementary when they add up to 180°.

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

Two angles are said to be complementary when they add up to 90°.

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

5 0

4 years ago