Answer:
11.4 years
Step-by-step explanation:
We assume you want to know the time it takes for Lucy's investment of $1200 to have a value of $6400. The compound interest formula is good for finding that.
FV = P(1 +r/n)^(nt)
for principal P invested at rate r per year for t years, compounded n times per year. We want to find t such that ...
6400 = 1200(1 +0.15/4)^(4t)
16/3 = 1.0375^(4t) . . . . divide by 1200
log(16/3) = 4t·log(1.0375) . . . . take logarithms
t = log(16/3)/(4·log(1.0375)) ≈ 11.4
It will take about 11.4 years for Lucy's investment value to be $6400.
Answer:
The correct option is C. 14 ft
Step-by-step explanation:
To calculate the height, we will follow the steps below;
Formula is given to be: h = 2A / b1 +b2
where h = height of the trapezoid b1 and b2 are the bases of the trapezoid and A is the area of the trapezoid
From the question given;
Area A =329 feet² b1 = 30 feet b2 =17 feet
We can now proceed to insert the values into the formula
h = 2A / b1 +b2
h= 2(329) / 30 + 17
h = 658 /47
h=14 feet
Answer:
Both are binomials.
Step-by-step explanation:
Given that
a) X is the number of dots on the top face of fair die that is rolled.
When a fair die is rolled, there will be 1 to 6 numbers on each side with dots in that. Each time a die is rolled the events are independent. Hence probability of getting a particular number in the die is 1/6. There will be two outcomes either the number or not the number. Hence X no of times we get a particular number of dots on the top face of fair die that is rolled is binomial with n = no of rolls, and p = 1/6
b) X is the number of defective parts in a sample of ten randomly selected parts coming from a manufacturing process in which 0.02% of all parts are defective.
Here X has two outcomes whether defective or non defective. EAch part is independent of the other in the sense that the probability for each trial is constant with 0.02% =p and no of trials = n = 10.
V = d/t = 8.8 miles/[80/60] hours = 6.6 miles/hour
t = d/v = d/6.6
Answer: d/6.6, where d is the number of miles to run.
