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3 years ago

Determine the length of side c??

Mathematics

1 answer:

Kisachek [45]3 years ago

3 0

Answer:

c = 13

Step-by-step explanation:

The Pythagorean theorem:

a^2 + b^2 = c^2

12^2 + 5^2 = c^2

144 + 25 = c^2

169 = c^2

c^2 = 169

c = 13

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Simplify as far as possible. 2√125−5√5

sveticcg [70]

Answer:

Step-by-step explanation:

Simplify (-10- square root of 125)/5. −10−√1255 - 10 - 125 5. Simplify the numerator.

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3 years ago

Read 2 more answers

Which expression has the same value as the expression 8x^2 + 2x - 6) - (5x^2 - 3x + 2)?

soldi70 [24.7K]

Answer D
use photomath and sub to pewdiepie

6 0

2 years ago

please help!!!!! what will be the balance in an account that was initially $400 and has been drawing 5.5% interest compounded co

Viktor [21]

Answer:

$621.08

Step-by-step explanation:

The formula for the amount (A) resulting from principal P being invested at rate r continuously compounded for period t is ...

A = Pe^(rt)

Filling in the given numbers and doing the arithmetic, we get ...

A = $400e^(0.055·8) ≈ $621.08

4 0

3 years ago

If K = F( A + B ) , find “ A ” if F = 2 , B = 3 , K = 10

Oxana [17]

Answer:

The value of A is 2

Step-by-step explanation:

F = 2 , B = 3 , K = 10

K = F( A + B )

10 = 2(A + 3)

10 = 2A + 6

Now, Subtract 6 from each side we get,

10 - 6 = 2A + 6 - 6

4 = 2A

2A = 4

Now, divide both side by 2 we get,

2A/2 = 4/2

A = 2

Thus, The value of A is 2

<h3>FOR VERIFICATION ONLY :-</h3>

K = F( A + B )

10 = 2(2 + 3)

10 = 2(5)

10 = 10

L.H.S = R.H.S

Hence Proved!

-TheUnknownScientist 72

7 0

2 years ago

5 points

jonny [76]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{2}x-5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 2 and passes through (4 , -3)

$(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y+3=2x-8\implies y=2x-11$

5 0

2 years ago