Answer:
George must run the last half mile at a speed of 6 miles per hour in order to arrive at school just as school begins today
Step-by-step explanation:
Here, we are interested in calculating the number of hours George must walk to arrive at school the normal time he arrives given that his speed is different from what it used to be.
Let’s first start at looking at how many hours he take per day on a normal day, all things being equal.
Mathematically;
time = distance/speed
He walks 1 mile at 3 miles per hour.
Thus, the total amount of time he spend each normal day would be;
time = 1/3 hour or 20 minutes
Now, let’s look at his split journey today. What we know is that by adding the times taken for each side of the journey, he would arrive at the school the normal time he arrives given that he left home at the time he used to.
Let the unknown speed be x miles/hour
Mathematically;
We shall be using the formula for time by dividing the distance by the speed
1/3 = 1/2/(2) + 1/2/x
1/3 = 1/4 + 1/2x
1/2x = 1/3 - 1/4
1/2x = (4-3)/12
1/2x = 1/12
2x = 12
x = 12/2
x = 6 miles per hour
9514 1404 393
Answer:
-361
Step-by-step explanation:
Your calculator can tell you the result. It is -361.
Start with the inner parentheses and work outward. Do multiplication and division in the order shown, left to right, before addition or subtraction.
-3[2/6+8{-9/3(8-5*3)-6}]
= -3[2/6+8{-9/3(8-15)-6}]
= -3[2/6+8{-9/3(-7)-6}]
= -3[2/6+8{-3(-7)-6}]
= -3[2/6+8{21-6}]
= -3[2/6+8{15}]
= -3[1/3+8{15}]
= -3[1/3+120]
= -3[361/3]
= -361
Answer:
explanation
Step-by-step explanation:
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