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andreev551 [17]
3 years ago
13

Need help fast .............................. Need help fast .............................. Need help fast .....................

......... Need help fast .............................. Need help fast ..............................

Mathematics
2 answers:
Sergio [31]3 years ago
7 0
The T is not congruent but it is similar
•
the square and rectangle are not congruent and they are not similar

•
The circles are congruent and they are similar

• And the triangles are congruent and similar
Ksju [112]3 years ago
7 0

Answer:

the T is not congruent but it is similar

•

the square and rectangle are not congruent and they are not similar

•

The circles are congruent and they are similar

• And the triangles are congruent and similar

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PLEASE HELP! I WILL MARK TOU AS BRAINLEIST!
san4es73 [151]

Answer:

a.Z(-2,1)

b.Z(1,1)

c.Z(-3,2)

Step-by-step explanation:

z(-2,3)

Imagine this point on a graph.

Translate it down two units :

the x stays -2, by going down the y decreases 2 so 3-2=1

Z(-2,1)

Translate Right three units : I'm assuming that we use the answer from the first translation

Z(-2,1)

The y doesn't change this time the x increases 3 since we're moving to the right.

Z(1,1)

Translate up 1 and left 4:

Z(1,1)

by moving up one we have Z(1,2) then by moving 4 to the left we get Z(-3,2)

Hope this helps :)

6 0
3 years ago
Read 2 more answers
If a the base on a logarithum is blank is it 1,0,or 10
anastassius [24]

Answer:

0 is the answer of to question

4 0
3 years ago
Find the value of x. <br>x = [?]​
cricket20 [7]
X=2
As both triangles share a same side length of 5, and the angles are both 30degrees, assuming the triangles meet at the centre of the circle then both sides (x) must be the same.
6 0
2 years ago
Read 2 more answers
4. Solve the equation using the quadratic formula.
Vikentia [17]

Answer:

A. x = -2, x = 1.25

Step-by-step explanation:

<u>Use the </u><u>quadratic</u><u> formula</u>

x = \frac{-b+\sqrt{b^{2}-4ac } }{2a}

Once in standard form, <u>identify</u> a, b, and c from the <u>original</u> equation and plug them into the <u>quadratic formula</u>.

4x² + 3x - 10 = 0

a = 4

b = 3

c = - 10

x = \frac{-3+\sqrt{3^{2}-4x4(-10) } }{2x4}

<u>Simplify</u>

<u>Evaluate the exponent</u>

x = \frac{-3+\sqrt{9-4x4(-10)} }{2x4}

<u>Multiply</u> the numbers

x = \frac{-3+\sqrt{9+160} }{2x4}

Add the <u>numbers</u>

x = \frac{-3+\sqrt{169} }{2x4}

Evaluate the <u>square root</u>

x = \frac{-3+13}{2x4}

<u>Multiply</u> the numbers

x = \frac{-3+13}{8}

<u>Separate</u><u> the equations</u>

To solve for the <u>unknown variable</u>, separate into two equations: one with a plus and the other with a minus.

x = \frac{-3+13}{8}

x = \frac{-3-13}{8}

<u>Solve</u>

Rearrange and isolate the <u>variable</u> to find each <u>solution</u>

x = - 2

x = 1.25

6 0
3 years ago
Read 2 more answers
H(t)=t^2+4t+3 what are the zeroes of the function? Write the smaller t first, and then the larger t second
Anuta_ua [19.1K]

Answer:

t = - 3, t = - 1

Step-by-step explanation:

Given

h(t) = t² + 4t + 3

To find the zeros equate h(t) to zero, that is

t² + 4t + 3 = 0

Consider the factors of the constant term (+ 3) which sum to give the coefficient of the t- term

The factors are + 3 and + 1, since

3 × 1 = 3 and 3 + 1 = 4, thus

t² + 4t + 3 = (t + 3)(t + 1) = 0

Equate each factor to 0 and solve for t

t + 3 = 0 ⇒ t = - 3

t + 1 = 0 ⇒ t = - 1

smaller zero is t = - 3

larger zero is t = - 1

5 0
3 years ago
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