Using the expression for the nth term of a sequence, find the first five terms of the sequence. Begin with n = 1.

1. write it on a piece of paper

stiv31 [10]

$\\ \sf\longmapsto 1\dfrac{1}{2}+2\dfrac{3}{4}$

$\\ \sf\longmapsto \dfrac{3}{2}+\dfrac{11}{4}$

$\\ \sf\longmapsto \dfrac{6+11}{4}$

$\\ \sf\longmapsto \dfrac{17}{4}$

2:-

$\\ \sf\longmapsto 4\dfrac{3}{7}+6\dfrac{1}{5}$

$\\ \sf\longmapsto \dfrac{31}{7}+\dfrac{31}{5}$

$\\ \sf\longmapsto \dfrac{155+225}{35}$

$\\ \sf\longmapsto \dfrac{380}{35}$

$\\ \sf\longmapsto 12$

3:-

$\\ \sf\longmapsto 4\dfrac{2}{5}+5\dfrac{2}{6}$

$\\ \sf\longmapsto \dfrac{22}{5}+\dfrac{32}{6}$

$\\ \sf\longmapsto \dfrac{132+160}{30}$

$\\ \sf\longmapsto \dfrac{292}{30}$

4:-

$\\ \sf\longmapsto 3\dfrac{7}{7}+3\dfrac{1}{3}$

$\\ \sf\longmapsto \dfrac{28}{7}+\dfrac{10}{3}$

$\\ \sf\longmapsto 4+\dfrac{10}{3}$

$\\ \sf\longmapsto \dfrac{12+10}{3}$

$\\ \sf\longmapsto \dfrac{22}{3}$

7 0

3 years ago

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When 5 is added to 2 times a number, the result is 45. find the number.

WINSTONCH [101]

A.

let the number be n.
2n+5=45
2n=40
n=20

3 0

3 years ago

The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms. How lo

liberstina [14]

Answer:

16.34 hours

Step-by-step explanation:

According to the given information we can see that the case is of exponential growth

Hence, we will use the formula

$A=P(2)^\frac{t}{24}$

Here A =800 is the amount that is needed to reach

P is the initial amount that is 500

We have to find the time it will take to reach 800 that is we need to find t

On substituting the values in the formula we get

$800=500(2)^\frac{t}{24}$

On simplification we get

$\Rightarrow\frac{8}{5}=(2)^\frac{t}{24}$

Taking log on both sides we get

$\Rightarrow\log\frac{8}{5}=\log(2)^\frac{t}{24}$

using $\log\frac{m}{n}=\log m-\log n$

And $\log a^m=m\log a$

$\Rightarrow\log{8}-\log{5}=\frac{t}{24}\log2$

Now substituting values of log 8=0.903, log 5=0.698 and log 2=0.301 we get

$\Rightarrow 0.903-0.698=\frac{t}{24}0.301$

$\Rightarrow 0.205=\frac{t}{24}0.301$

$\Rightarrow \frac{0.205}{0.301}\cdot 24=t$

$\Rightarrow t=16.34$

8 0

4 years ago

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Can someone explain/show me how to do this?Absolute Value Functions

dedylja [7]

Domain: -∞<x<∞
Range: -∞<x<∞
X-Intercept: x=0
Y-Intercept: y=0
Increasing on the interval of 0<x<∞
Decreasing on the interval of -∞<x<0

When A=0, the graph equals y=0
- When A is greater than 1, it makes the graph skinnier than f(x)=|x|
- When A is less than 1 but greater than 0, it makes the graph fatter than f(x)=|x|
- When A turns negative, it flips the graph upside down.

-When B is greater than 0, it translates the graph to the right
- When B is less than 0, it translates the graph to the left

When C is greater than 0, the graph moves upwards
When C is less than 0, the graph moves downwards

3 0

3 years ago

Find the equation of the graphed line.

yulyashka [42]

It’s the first one; a)

3 0

3 years ago

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