the only thing you need to do is separate m:
2/7m= 3/14 + 1/7
2/7m= 5/14
m= (5/14)/(2/7)
m= 5/14 × 7/2
m= 35/28
m= 5/4
Answer:
-5cd
Step-by-step explanation:
<u>Simplifying:</u>
- -3cd - d(2c - 4) - 4d = ⇒ parenthesis
- -3cd - 2cd + 4d - 4d = ⇒ simplify like terms
- -5cd ⇒ answer
The first choice is correct one.
0.0011961722 i used a calculater
Answer:
Step-by-step explanation:
When learning about commutative and associative properties, we learn that ...
a + b = b + a . . . . . addition is commutative
ab = ba . . . . . . . . . multiplication is commutative
But we also know that ...
a - b ≠ b - a . . . . . . subtraction is not commutative
a/b ≠ b/a . . . . . . . . division is not commutative
__
We also learn that ...
a + (b+c) = (a+b) +c . . . . addition is associative
a(bc) = (ab)c . . . . . multiplication is associative
And of course, ...
a - (b -c) ≠ (a -b) -c . . . . subtraction is not associative
a/(b/c) ≠ (a/b)/c . . . . . . . division is not associative
_____
However, you can use associative and commutative properties in problems involving subtraction and division if you write the expression properly:
a - (b - c) = a +(-(b -c)) = a +((-b) +c) = (a +(-b)) +c . . . . keeping the sign with the value makes it an addition problem, so the associative property can apply
(a/b)/c = (a(1/b))(1/c) = a(1/b·1/c) = writing the division as multiplication by a reciprocal makes it so the associative property can apply
The first one and the last one is true
the rest are false
