Price of movie ticket in Japan is x=7.362$
Price of movie ticket in Switzerland is y=13.652$
Step-by-step explanation:
Let, Price of movie ticket in Japan is x
Price of movie ticket in Switzerland is y
Statement 1 : Total of 79.39$ of three movie ticket in Japan and two movie ticket in Switzerland
We write, 3x+2y=79.39 ( Equation 1 )
Statement 1 : Total of 75.68$ of two movie ticket in Japan and three movie ticket in Switzerland
We write, 2x+3y=75.68 ( Equation 2 )
Solving by method of elimination
Multiplying equation 1 by 2, we get
6x+4y=158.78
Multiplying equation 2 by 3, we get
6x+9y=227.04
Subtracting both the linear equation,
6x+4y=158.78
- 6x+9y=227.04
_______________
0x-5y=(158.78-227.04)
-5y=(-68.26)
5y=68.26
y=13.652$
Replacing value of y in any equation
3x+2y=79.39
3x+2(13.652 )=79.39
x=17.362$
Thus,
Price of movie ticket in Japan is x=7.362$
Price of movie ticket in Switzerland is y=13.652$
Answer:
45+n;when n=1.1, the value is 46.1
Step-by-step explanation:
45 + 1.1
45 . 0
+ 1 . 1 ____________
4 6 . 1
46.1
You just add 45 + 1.1 and whatever you get is your answer
Answer:
32^(4/5)=16
Step-by-step explanation:
Log base a (b)=c
a^c=b
Option 4
Answered by Gauthmath must click thanks and mark brainliest
