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Delvig [45]
4 years ago
14

What are the zeros of the quadratic function? f(x)=3x2−300 Enter your answers in the boxes.

Mathematics
1 answer:
nata0808 [166]4 years ago
5 0
Hi there!

We can find the zeros of a function by solving f(x) = 0. We find the following:

3 {x}^{2} - 300 = 0
Add 300 to both sides.

3 {x}^{2} = 300
Divide by 3.

{x}^{2} = 100
Take the root and minus root of both sides.

x = \sqrt{100} = 10 \\ or \\ x = - \sqrt{100} = - 10

Therefore, the zeros are
x = 10 and x = -10.

~ Hope this helps you!
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ankoles [38]

\bold{Heya!}

Your answer to this is:

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

<h2>→ <u>EXPLANATION :-</u></h2>

<u />

<u />\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: (1)

\sf{Apply \: rule:} \: (a) = a

\sf{(1) = 1

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0} \: ^. \: 1

\sf{\frac{1}{1 \: + \:1} = \frac{1}{2}

\sf{\frac{2^1^0^0}{1 \: + \: x^2^0^0} ^.^ \: 1 \: = \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

\sf{= \frac{1}{2} \: + \frac{2}{1 \: + \: x^2} \: + \: \frac{1}{1 \: + \: x^4} \: + \: \frac{2^1^0^0}{1 \: + \: x^2^0^0}

Hopefully This Helps ! ~

#LearnWithBrainly

\underline{Answer :}

<em>Jaceysan ~</em>

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2 years ago
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Dafna1 [17]

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Step-by-step explanation:

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A number cube is rolled 360 times and the results are recorded as follows: 41 ones, 54 twos, 62 threes, 75 fours, 33 fives, and
cestrela7 [59]
Let's attribute a to equal probability of 2 and b to equal probability of 3
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now simply divide 116 by 360 and you get your answer which is 0.32
A is the correct answer my dude
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3 years ago
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