Question

What are the coordinates of the point LaTeX: \frac{3}{4}\:3 4of the way from A to B? coordinate plane with line segment AB. Point A is at -5, -4 and point b at -3, 3

Answer 1

Answer: $\left(\dfrac{-7}{2},\dfrac{5}{4}\right)$.

Step-by-step explanation:

It is given that Point A is at (-5, -4) and point B at (-3, 3).

We need to find the coordinates of the point which is 3/4 of the way from A to B.

Let the required point be P.

$AP:AB=3:4$

$AP:PB=AP:(AB-AP)=3:(4-1)=3:1$

It means, point P divides segment AB in 3:1.

Section formula:  If a point divides a line segment in m:n, then

$\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)$

Using section formula, we get

$P=\left(\dfrac{3(-3)+1(-5)}{3+1},\dfrac{3(3)+1(-4)}{3+1}\right)$

$P=\left(\dfrac{-9-5}{4},\dfrac{9-4}{4}\right)$

$P=\left(\dfrac{-14}{4},\dfrac{5}{4}\right)$

$P=\left(\dfrac{-7}{2},\dfrac{5}{4}\right)$

Therefore, the required point is $\left(\dfrac{-7}{2},\dfrac{5}{4}\right)$.