Question

In a bag, there are blue, red, and green jolly ranchers. If the probability of getting a blue is 2/9 and the probability of getting a red is 1/3 ,what is the probability of getting a green jolly rancher?

Answer 1

Answer:

P(green) = 4/9

Step-by-step explanation:

The probability of getting all items is 1

Since we only have blue red and green ,

P(red) + P(blue) + P(green) =1

1/3 + 2/9 + P(green) =1

Getting a common denominator of 9

3/9 + 2/9 + P(green) = 9/9

5/9 + P(green) = 9/9

Subtract 5/9 from each side

5/9  -5/9 + P(green) = 9/9 - 5/9

P(green) = 4/9

Answer 2

Answer:

The probability of getting a green jolly rancher is $\frac{4}{9}$ .

Step-by-step explanation:

We are given that in a bag, there are blue, red, and green jolly ranchers. The probability of getting a blue is 2/9 and the probability of getting a red is 1/3.

Let the Probability of getting a blue jolly rancher = P(B) = $\frac{2}{9}$

            Probability of getting a red jolly rancher = P(R) = $\frac{1}{3}$

            Probability of getting a green jolly rancher = P(G)

Now, as we know that the Sum of all probability cases of any event is 1.

That is, here the event is that the bag contains blue, red and green jolly ranchers. There is not any chance of getting a jolly ranches of color other than this which means;

Probability of getting blue rancher + Probability of getting red rancher + Probability of getting green rancher = 1

          $\frac{2}{9}$ + $\frac{1}{3}$ + Probability of getting green rancher = 1

Probability of getting green rancher = $1 - \frac{2}{9} - \frac{1}{3}$ = $1-\frac{5}{9}$

                                                            = $\frac{4}{9}$

Therefore, probability of getting a green jolly rancher is  $\frac{4}{9}$ .