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Afina-wow [57]
3 years ago
9

A triangle has two sides measuring 16 and 21. The included angle is 116°. What is the length of the side opposite the 116° angle

?

Mathematics
1 answer:
aleksley [76]3 years ago
4 0

Answer: A. 31.5

Step-by-step explanation:

Using law of cosine because it is side angle side

a=16

b=21

angle = 116

c^2=a^2+b^2-2ab cosC, let C be the angle given

c^2=(21)^2+(16)^2-2(16)(21) cos(116)

c^2=441+256-672 cos(116)

i used a ti-89 and answered the right side and got

(you can find a ti-89 simulator online, but for problems like this make sure it is in degree mode)

991.585

c^2=991.585

take square root of both sides

=31.4894, which if you round it up it would be 31.5, so the answer would be A

therefore:

a=16

b=21

c=31.5

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Answer:

$\[x^2 + 22x + 121\]$

Step-by-step explanation:

Given

$\[x^2 + 22x + \underline{~~~~}.\]$

Required

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Represent the blank with k

$\[x^2 + 22x + k\]$

Solving for k...

To do this, we start by getting the coefficient of x

Coefficient of x = 22

<em />

Divide the coefficient by 2

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Take the square of this result, to give k

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Substitute 121 for k

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The expression can be factorized as follows;

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