Help! i need to answer this before 11:59pm EST, Today !!, i would appreciate your help.

Mathematics

1 answer:

Arada [10]4 years ago

3 0

Answer:

0.18 sec or 3.4 sec.

For second part, it will take 3.7 sec.

First part:

Set h(t) = 17and solve for t.

-16t²+ 58t + 7= 17

-16t² + 58t - 10 = 0

Solve this quadratic equation for t. You should get 2 positive solutions. The lower value is the time to reach 17 on the way up, and the higher value is the time to reach 17 again, on the way down.

Second part:

Set h(t) = 0 and solve the resulting quadratic equation for t. You should get a negative solution (which you can discard), and a positive solution. The latter is your answer.

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1.) A projectile launched straight up into the air with an initial velocity of 20 meters per second from a height of 10 meters.

Dafna1 [17]

Hello,

I have just answered the question

gravity on earth :g=9.81 m/s²

$h(t)=-\frac{g*t^2}{2}+v_{0}*t+h_{0}$
9.81/2≈4.9
$v_{0}\ is\ initial\ speed$
$h_{0}\ is\ initial\ height$

Answer 1

2)
h(t)=-4.9*t²+20*t+10

To hit the ground ht(t)=0
==> -4.9*t²+20*t+10=0
Δ=20²+4*4*10=560=23,6643...²

t=(-20-4√35)/(-4.9*2)=4,4555...(s)

t=(-20+4√35)/(-2*4.9)=-0,37391... to exclude (time must be >0)

4 0

3 years ago

Solve the equation for x: | 4x - 3] = 7

Soloha48 [4]

Answer:

x=-1, 5/2.

Step-by-step explanation:

abs(4x-3)=7

4x-3=7, 4x-3=-7

4x=7+3=10

x=10/4=5/2

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