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yan [13]
4 years ago
12

Go do I solve this problem (42+18−54)×√100÷(9√2−11×6)×(36−34×1√4)

Mathematics
1 answer:
yanalaym [24]4 years ago
8 0
Use the order of operations 
<span>(42 + 18 − 54) × √100 ÷ (9√2 − 11 × 6) × (36 − 34 × 1√4)
6 </span>× 10 ÷ (9√2 − 66) × (36 − 34√4)
60 ÷ (9√2 − 66) × (36 − 68)
60 ÷ (9√2 − 66) × (-32)
-1920÷(9√2 − 66)
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Find the second, fifth, and ninth terms of a sequence where the first term is 65 and the common difference is -7.
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There are multiple ways to do this.

The easiest is to just continuously subtract 7 from 65 the numbers of times needed.

But most math teachers will have you use the equation ar^n-1 where a= the first term (65), r=ratio (-7), and n=the term you need (second, fifth, and ninth). 

So to solve you just plug your values in as so
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Step-by-step explanation:

if solving for y

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Answer:

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Step-by-step explanation:

<em>We are shown a scatter plot and the equation of best fit line. The eqaution explains the general trend of the scatterplot. Using the equation we can find the money earned for 5 chores</em>

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