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NeX [460]
3 years ago
14

What's the answer for W-y=3w-10

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Answer:

Step-by-step explanation:

if solving for y

solve for y by simplifying both sides of equation, then isolating the variable.

y=-3w+10+W

if solving for W

W=3w-10+y

if solving for w

w=W/3 - y/3 + 10/3

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21 years ago Alvin was 11 times older than Tomio. The sum of their present age is 54.
DaniilM [7]

Answer:

Not sure exactly what answer you are looking for. But I assume it is the ages of them. Their original ages would be Tomio - 1 year old, Alvin - 11 years old. Now, Tomio - 22, Alvin - 32

Step-by-step explanation:

1(tomio) x 11 = 11 (alvin) (add 21 to these)

22+32=54

hope that makes sense

6 0
2 years ago
How many groups of 3/4 are in each of the following questions?
marysya [2.9K]

Answer:

12 1/3

Step-by-step exp

First, you need to add up 11/4 and

6 1/2

11/ 4 + 6 1/2 = 11/4 + 13/2 = 37 / 4

To find how many 3/4 we have in 37/4, we simply dividw 37/4 by 3/4

37/4 ÷ 3/4

= 37/4 × 4/3 (4 will cancel out 4)

= 37/3

=12 1/3

3 0
3 years ago
Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

6 0
3 years ago
Read 2 more answers
JO. Jeff buys 3 boxes of cereal for $2.99 each a gallon of
kramer
First add up the total of the food. Then, multiply it by .2 (20%), and subtract that number from your total. You will get the price Jeff paid for his food.

6 0
2 years ago
Solve for x on each of these questions please!
IgorLugansk [536]

Answer:

1. x = 10

2. x = 4

Step-by-step explanation:

I use the angle ABC method:

AB² + AC² = BC²

6² + 8² = x²

x = 10

AB² + AC² = BC²

3² + x² = 5²

x = 4

<em>H</em><em>O</em><em>P</em><em>E</em><em> </em><em>T</em><em>H</em><em>I</em><em>S</em><em> </em><em>H</em><em>E</em><em>L</em><em>P</em><em>S</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>H</em><em>A</em><em>V</em><em>E</em><em> </em><em>A</em><em> </em><em>N</em><em>I</em><em>C</em><em>E</em><em> </em><em>D</em><em>A</em><em>Y</em><em> </em><em><</em><em>3</em>

5 0
2 years ago
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