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notsponge [240]
3 years ago
6

Help whats the absolute value

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0
|a|=  \left\{\begin{array}{ccc}a&if&a\geq0\\-a&if&a \ \textless \  0\end{array}\right\\\\examples\\3\geq 0\to|3|=3\\102\geq0\to|102|=102\\0\geq0\to|0|=0\\-4 \ \textless \  0\to|-4|=-(-4)=4\\-105 \ \textless \  0\to|-105|=105

OK. Let's go to your question:

a) |-100| - 98 = 100 - 98 = 2

b) 5|2 - 8| = 5|-6| = 5 · 6 = 30
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Answer:

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Step-by-step explanation:

15 + 18(.5) = 24

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Use the disruptive property to simplify the expression 4(2x-4)
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Answer:

C.8x - 16

Step-by-step explanation:

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5 0
3 years ago
5x – 12y – 17 = 0<br> 1*9(x + 2) - (y + 1) + 3 = 0
valentina_108 [34]

Answer: x=\frac{12y+17}{5}

y=\frac{-5x+17}{-12}

x=\frac{y-20}{9}

y=9x+20

Step-by-step explanation:

5x-12y-17=0 (plus 17 from both sides)

5x-12y=17 (plus 12y from both sides)

5x=12y+17 (divide 5 from everything)

x=\frac{12y+17}{5}

5x-12y-17=0 (plus 17 from both sides)

5x-12y=17 (minus 5x from both sides)

-12y=-5x+17 (divide everything by -12)

y=\frac{-5x+17}{-12}

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1*9x+18-y-1+3=0 (times 9x by 1)

9x+18-y-1+3=0 (combine like terms)

9x-y+20=0 (minus 20 from both sides)

9x-y=-20 (plus y to both sides)

9x=y-20 (divide 9 from both sides)

x=\frac{y-20}{9}

1*9(x+2)-(y+1)+3=0 (distribute 9 to x and to 2) (distribute -1 to y and to 1)

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9x+18-y-1+3=0 (combine like terms)

9x-y+20=0 (minus 20 from both sides)

9x-y=-20 (minus 9x from both sides)

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3 0
3 years ago
-4 (r + 2) = 4 (2 - 2r)
Nady [450]

Answer:

r=4

Step-by-step explanation:

Let's solve your equation step-by-step.

−4(r+2)=4(2−2r)

Step 1: Simplify both sides of the equation.

−4(r+2)=4(2−2r)

(−4)(r)+(−4)(2)=(4)(2)+(4)(−2r)(Distribute)

−4r+−8=8+−8r

−4r−8=−8r+8

Step 2: Add 8r to both sides.

−4r−8+8r=−8r+8+8r

4r−8=8

Step 3: Add 8 to both sides.

4r−8+8=8+8

4r=16

Step 4: Divide both sides by 4.

4r

4

=

16

4

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Answer:

r=4

3 0
3 years ago
Show work too please :)
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5 0
2 years ago
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