If resistors are in series, so the current $I$ is the same in all of them. In this problem we have four resistors. So, we can get a relationship between the Equivalent resistance of series combination and the four resistors as follows:

$R_{eq}=R_{1}+R_{2}+R_{3}+R_{4}$

$R_{eq}$ is the total resistance $50\Omega$ . Moreover:

$R_{1}=5\Omega \\ R_{2}=10\Omega \\ R_{3}=15\Omega$

Therefore:

$50=5+10+15+R_{4} \\ \\ R_{4}=50-(5+10+15) \\ \\ R_{4}=50-30 \\ \\ \boxed{R_{4}=20\Omega}$

7 0

3 years ago

I need help plz<br> 12<br> 10<br> 8<br> 12.5

kherson [118]

Answer:

Step-by-step explanation:

5 0

3 years ago

The following dot plot represents a random sample of elementary students and the number of children that live in their home.

NISA [10]

None of the households in the United States contain five children.

The majority of the households in the United States, with at least one child, contain less than three children.

If thats wrong dont go off on me

~s9154499~

~Mia for short~

7 0

3 years ago

(From workbook MATH 8A)​

(From workbook MATH 8A)