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Novay_Z [31]
3 years ago
11

Frank measured 56 cm. The actual length was 61 cm. Which expression shows his percent error?

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer: 8.54701% difference

Step-by-step explanation: (61-56)/[(61+56)/2] x 100= 8.55%

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