Find the inverse of the function y=2x^2
2 answers:
to find the inverse exchange the x and y and then solve for y
y =2x^2
x =2y^2
divide by 2
x/2 = y^2
take the square root of each side
sqrt(x/2) =y
the inverse of y =2x^2 is sqrt(x/2)
X=2y2x=2y2
Solve for yy.
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y=√2x2,−√2x2y=2x2,-2x2
Solve for yy and replace with f−1(x)f-1(x).
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f−1(x)=√2x2,−√2x2
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x^2 + 9.5^2 = 11^2
x^2 + 90.25 = 121
x^2 = 30.75
x^2 = 
x = 5.54cm
rounded: 5.5cm
answer: D
Answer:
n=-N/5+9/5
Step-by-step explanation:
Answer:
25
Step-by-step explanation:

Hence 11% represents 25 students.
The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is

a1=1
r=2
we want to find

(since we minus 1, the highest exponet is 9 so add 1 to make it correct)


