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12345 [234]
3 years ago
11

Please help PLEASE BRAINLY I WILL GIVE U 5 STARS

Mathematics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:<em> 20 degrees</em>

Step-by-step explanation:

Find the 180 (degrees angle)= angle CD

180 degrees-110 degrees= 70 degrees

By using the OAT (opposite angle theorem), the opposite of the angle OD (you know what i mean) will be 70 degrees too. So, Angle BO is 70 degrees too. We know the right angle there is 90 degrees because of the square sign so, create another 180 degrees angle but subtract 160 degrees (70+90) from 180 degrees which is 20 degrees.

Give me 5 stars if you like it

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100000 less than 560313 is
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100000
-560313

460313
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3 years ago
PLZ HELPP 10 POINTS PLZZZ
kenny6666 [7]

Answer:

No,yes,yes,no,yes

Step-by-step explanation:

4 0
3 years ago
Table of values for y=2x^2-2x
Pachacha [2.7K]

Answer:

x= -2, -1, 0, 1, 2\\y= 12, 4,0,0,4

Step-by-step explanation:

let me know if this is right please :(

4 0
2 years ago
What is the answer to 4x&lt;12
Korolek [52]
All you'd do is divide by 4 on both sides,

4/4 = 1
12/4 = 3

Your Answer:
x < 3

5 0
3 years ago
Read 2 more answers
Please please please need help on 3 and 4 I’m really lost on them
Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

     |_________________

        1      -1      -2     2      0

Therefore x=-1 is a zero

x^3-x^2-2x+2=0

      |  1    -1     -2    2

1      |  0     1     0     2

      |___________________

          1     0   -2   0

x=1 is the zero

x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

5 0
3 years ago
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