The probability that a two-digit number selected at random has a tens digit less than its units digit is 0.2667 (4/15).

There are 90 two-digit numbers (99-9). Of these, six numbers are divisible by 15 (15, 30, 45, 60, 75, 90). This is also divisible by 5. Therefore, the preferred case is 30-6 = 24. Therefore, the required probability is 24/90 = 4/15.
The probability of an event can be calculated by simply dividing the number of favorable results by the total number of possible results using a probabilistic expression. Whenever you are uncertain about the outcome of an event, you can talk about the probability of a particular outcome, that is, its potential.
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Let no be x
Acc to ques
X + 2(1/x) = 3
X + 2/x = 3
X^2 + 2 = 3x
X^2 - 3x + 2 = 0
X^2 - x - 2x + 2 = 0
X (x-1) - 2 (x-1) = 0
(x-2) (x-1) = 0
X= 2 or x =1
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<span>The difference between the larger result and the smaller result was 10.
Suppose the 4 digits numbers are abcd and pqrs
Here, 1st Number is = 1000*a + 100*b + 10*c + d
and 2nd</span> Number is = 1000*ap + 100*q + 10*r + s
Then, since Kent made an error if 1 in tens columns and Harold added it correct, so the difference will be of 10 points.
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