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GarryVolchara [31]
3 years ago
14

15. In AABC if mZA is thirteen less than mzC and mZB is eleven less than four times m

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

m\angle A=21°

m\angle B=125°

m\angle C=34°

Step-by-step explanation:

Let the measure of angle C be x°.

Given:

In triangle ΔABC,

m\angle A is thirteen less than m\angle C and m\angle B is eleven less than four times m\angle C. This gives,

m\angle A = x-13

m\angle B=4x-11

Also, m\angle C=x

Now, for a triangle, the sum of all its interior angles is equal to 180°.

Therefore, m\angle A + m\angle B + m\angle C=180

Plug in all the values and solve for x. This gives,

x-13+4x-11+x=180\\6x-24=180\\6x=180+24\\6x=204\\x=\frac{204}{6}=34

Therefore, measure of angle C is 34°.

Measure of angle A is, m\angle A=x-13=34-13=21°.

Measure of angle B is, m\angle B=4x-11=4(34)-11=136-11=125°.

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