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MrRa [10]
3 years ago
6

Solve the system of equations below. 4x+y=16 2x+3y=-2 A. (4,-5) B. (5,-4) C. (5,4) D. (-5,4)

Mathematics
2 answers:
san4es73 [151]3 years ago
7 0

Answer:

Option B is correct.

(5, -4)

Step-by-step explanation:

Given the system of equations:

4x+y = 16               ......[1]

2x+3y = -2             .....[2]

Multiply equation [2] by 2 both sides we have;

4x+6y = -4                      .....[3]

Subtract equation [3] from [1] we have;

4x+y-4x-6y= 16+4  

Combine like terms;

-5y = 20

Divide both sides by -5 we have;

y  = -4

Substitute this value y in [1] we have;

4x+(-4) = 16

⇒4x - 4 = 16

Add 4 to both sides we have;

4x = 20

Divide both sides by 4 we have;

x = 5

therefore, the solutions of the given systems is, (5, -4).

zlopas [31]3 years ago
4 0
Your answer is (5,-4) 
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