Question

Solve the system of equations below. 4x+y=16 2x+3y=-2 A. (4,-5) B. (5,-4) C. (5,4) D. (-5,4)

Answer 1

Answer:

Option B is correct.

(5, -4)

Step-by-step explanation:

Given the system of equations:

$4x+y = 16$               ......[1]

$2x+3y = -2$             .....[2]

Multiply equation [2] by 2 both sides we have;

$4x+6y = -4$                      .....[3]

Subtract equation [3] from [1] we have;

$4x+y-4x-6y= 16+4$  

Combine like terms;

$-5y = 20$

Divide both sides by -5 we have;

y  = -4

Substitute this value y in [1] we have;

4x+(-4) = 16

⇒4x - 4 = 16

Add 4 to both sides we have;

4x = 20

Divide both sides by 4 we have;

x = 5

therefore, the solutions of the given systems is, (5, -4).

Answer 2

Your answer is (5,-4)