Solve the system of equations below. 4x+y=16 2x+3y=-2 A. (4,-5) B. (5,-4) C. (5,4) D. (-5,4)
2 answers:
Answer:
Option B is correct.
(5, -4)
Step-by-step explanation:
Given the system of equations:
......[1]
.....[2]
Multiply equation [2] by 2 both sides we have;
.....[3]
Subtract equation [3] from [1] we have;
Combine like terms;
Divide both sides by -5 we have;
y = -4
Substitute this value y in [1] we have;
4x+(-4) = 16
⇒4x - 4 = 16
Add 4 to both sides we have;
4x = 20
Divide both sides by 4 we have;
x = 5
therefore, the solutions of the given systems is, (5, -4).
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Hello :D
Answer:
A.
Step-by-step explanation:
First, you add by 14 both sides of an equation.
-14-5y+14>-64+14
Then, simplify by equation.
-64+14=-50
-5y>-50
Multiply -1 both sides.
(-5y)(-1)<(-50)(-1)
5y<50
Divide by 5 both sides of an equation.
5y/5<50/5
Divide numbers from left to right.
50/5=10
y<10 is the correct answer.
Hope this helps you! :D