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sp2606 [1]
3 years ago
13

explain the absorption of amino acids, monosaccharides, and fatty acids from substances in the small intestine

Biology
1 answer:
sattari [20]3 years ago
4 0

Answer: Amino acids and monosaccharides enter the cell through facilitated diffusion, and fatty acids are transformed to chylomicrons in the cell.

Explanation:

To understand how humans obtain energy from their environment, one has to understand some basic concepts:

1. Humans ingest foods that tend to be polymers, meaning that the macromolecules are organized in more complex structures and can’t be absorbed directly.

2. Our gastrointestinal tract is a specialized arrangement of organs that are in charge of digesting these polymers to smaller molecules, called monomers, that the cells lining the intestinal tract (enterocytes) can absorb.

The polymers that we obtain from the environment are proteins, carbohydrates, and fats, while the monomer that can be absorbed are amino acids, monosaccharides, and fatty acids, respectively.

Polymer digestion begins in the oral cavity, since saliva has some enzymes that can start this process (i.e: amylase, which is an enzyme that cleaves carbohydrates).

Afterwards, in the stomach, acidic chyme assist to breakdown all food element that are polymers. Additionally, some specialized cells that line the stomach cavity release proteolytic enzymes to cleave proteins (i.e. pepsinogen → pepsin. The active enzyme is pepsin, but in the cell it is stored as a zymogen, an inactive enzyme, so it does not affect the cell. The zymogen is activated when it is released in the stomach cavity).

In the first part of the small intestine, called duodenum, the food bolus will be exposed to bile and pancreatic juice, which will continue to aid the breakdown of proteins and carbohydrates. Additionally bile salts will act as act as emulsifiers, producing micelles which are more readily digested by pancreatic enzymes (lipase) into fatty acids that may be absorbed by the cells forming the lining of the gut.

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An appropriate volume to load on an average agarose gel is 12 ul, so:

2 ul Loading Buffer + 9.85 ul dH2O + 0.15 ul DNA Ladder = 12 ul

But since 0.15 ul is a very small volume and mistakes could be made while measuring it, let's make double:

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Answer:

Damian here!(ノ◕ヮ◕)ノ*:・゚✧

Explanation:

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Hope this helps? :))

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Explanation:

From Google

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