Two consecutive even Integers whose product is 80

What is the n in 4 1/2 = 1 1/2n; n =

jasenka [17]

Answer:

9/11

Step-by-step explanation:

4 1/2= 9/2=11/2n

so n =9/11

so 9/2=11/2*9/11

8 0

3 years ago

Determine whether the lines given are parallel, perpindicular, or neither

mezya [45]

This question has to do with slope. If two lines share the same slope but different points, then there are parallel. If their slopes are negative reciprocals (like -2 and 1/2), then they are perpendicular.
y = 3x - 7 and y = 3x + 1 have different points but both have a slope of 3, where y = mx+b,
m = slope. Therefore these two lines are parallel.

4 0

4 years ago

Find the volume of the cylinder. Round your answer to the nearest tenth.

ludmilkaskok [199]

Answer:

1526.8 ft ^3

Step-by-step explanation:

the volume of a cylinder formula is V=π x r^2 x h

= pi x 9^2 x 6

= pi x 81 x 6

=1526.8 ft ^3

7 0

3 years ago

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It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains

sdas [7]

Answer:

$X \sim N(100,15)$

Where $\mu=100$ and $\sigma=15$

We select a sample of n=16 and we are interested on the distribution of $\bar X$ , since the distribution for X is normal then we can conclude that the distribution for $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Because by definition:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$E(\bar X) = \mu$

$Var(\bar X) = \frac{\sigma^2}{n}$

And for this case we have this:

$\mu_{\bar X}= \mu = 100$

$\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

$X \sim N(100,15)$

Where $\mu=100$ and $\sigma=15$

We select a sample of n=16 and we are interested on the distribution of $\bar X$ , since the distribution for X is normal then we can conclude that the distribution for $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Because by definition:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$E(\bar X) = \mu$

$Var(\bar X) = \frac{\sigma^2}{n}$

And for this case we have this:

$\mu_{\bar X}= \mu = 100$

$\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75$

6 0

3 years ago

Some people advise that in very cold weather, you should keep the gas tank in your car more than half full. Irene's car had 5.

NARA [144]

49 dollars 3.50x14 hope this helps

4 0

3 years ago

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