What is the recursiveformula for this geometric sequence? 4,-12,36,108

Mathematics

1 answer:

Vlad1618 [11]4 years ago

8 0

Answer:

a[1] = 4

a[n] = -3·a[n-1]

Step-by-step explanation:

The sequence given is not a geometric sequence, since the ratios of terms are -3, -3, 3 -- not a constant.

If we assume that the last given term is supposed to be -108, then the common ratio is -3 and each term is -3 times the previous one. That is expressed in a recursive formula as ...

a[1] = 4 . . . . . . . . . . . first term is 4

a[n] = -3·a[n-1] . . . . . each successive term is -3 times the previous one

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