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Akimi4 [234]
4 years ago
10

What is the recursiveformula for this geometric sequence? 4,-12,36,108

Mathematics
1 answer:
Vlad1618 [11]4 years ago
8 0

Answer:

  a[1] = 4

  a[n] = -3·a[n-1]

Step-by-step explanation:

The sequence given is not a geometric sequence, since the ratios of terms are -3, -3, 3 -- not a constant.

If we assume that the last given term is supposed to be -108, then the common ratio is -3 and each term is -3 times the previous one. That is expressed in a recursive formula as ...

  a[1] = 4 . . . . . . . . . . .  first term is 4

  a[n] = -3·a[n-1] . . . . . each successive term is -3 times the previous one

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Answer:

option B (28/52)

Step-by-step explanation:

from probability

P(A∪B)=P(A)+P(B)-P(A∩B)

where

P(A∪B) = probability that event A or B happen

P(A∩B) = probability that event A and B happen simultaneously

P(A) =  probability that event A happen

P(B) =  probability that event B happen

the probability that the card is special or red

P( special or red)= P(special) + P(red) - P( special and red)

since

P(special)= 4/52

P(red) = 26/52

P( special and red) = 2/52

therefore

P( special or red)= 4/52 + 26/52 -  2/52 = 28/52

P( special or red)= 28/52

(option B)

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4 years ago
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https://www.mathpapa.com/algebra-calculator.html

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Step-by-step explanation:

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