All categories

3 years ago

Can someone help? it’s algebra 2, and due tonight

Mathematics

1 answer:

Kryger [21]3 years ago

3 0

Answer:

B 71/8

Step-by-step explanation:

2x² - 5x = -12

2x² - 5x + 12 = 0 (EQ 1)

expand 2(x - p)² + q = 0 ,

since (x - p)² = x² - 2xp + pq,

2x² - 4xp +2p² + q = 0 (EQ 2)

compare x⁰ (just a number, without x) in EQ 1 and EQ 2.

2p² + q = 12 (EQ 3)

compare x in EQ 1 and EQ 2,

-4p = -5

p = 5/4

Substitute p=5/4 into EQ 3,

2(5/4)² + q =12

q = 12 - 2(5/4)²

q= 71/8

You might be interested in

I didnt put the answer choices because ppl be putting random stuff

lesya692 [45]

I’m pretty sure the answer is 127.48 ,but I could be wrong.

5 0

3 years ago

How do i do this help

Ratling [72]

I don't know if u can see it, but there.
X=12
Y=15
Z=20

5 0

3 years ago

In Ms. Perron's class, 75% of the studnetw are doys. There are 18boys in the class. What is the totla numder of students in Ms.

Anastasy [175]

Your answer should be 24

6 0

4 years ago

Find the value g(-2), where g is defined below.<br> g(x) = 2x^2- 4x – 4

DanielleElmas [232]

Answer:

Step-by-step explanation:

For this question, simply plug in -2 for x:

$g(-2)=2(-2)^2-4(-2)-4\\g(-2)=2(4)+8-4\\g(-2)=8+8-4\\g(-2)=12$

Hope this helps!!

8 0

3 years ago

Need help with this!!!!!!!!

zzz [600]

The linear combination method is the same as the elimination method. Let's multiply the second equation by -2 so the x terms cancel each other out. When we do that we get a system of $2x-3y=13$ and $-2x-4y=8$ . The x-terms cancel each other out giving us $-7y=21$ and y = -3. Now sub -3 into one of the equations to solve for x. x+2(-3)=-4, and x - 6 = -4. x = 2. So the solution for our system is (2, -3)

4 0

4 years ago