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denis-greek [22]
4 years ago
5

Can someone help? it’s algebra 2, and due tonight

Mathematics
1 answer:
Kryger [21]4 years ago
3 0

Answer:

B 71/8

Step-by-step explanation:

2x² - 5x = -12

2x² - 5x + 12 = 0 (EQ 1)

expand 2(x - p)² + q = 0 ,

since (x - p)² = x² - 2xp + pq,

2x² - 4xp +2p² + q = 0 (EQ 2)

compare x⁰ (just a number, without x) in EQ 1 and EQ 2.

2p² + q = 12 (EQ 3)

compare x in EQ 1 and EQ 2,

-4p = -5

p = 5/4

Substitute p=5/4 into EQ 3,

2(5/4)² + q =12

q = 12 - 2(5/4)²

q= 71/8

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Step-by-step explanation:

do 320 +320 untill you get to 1,600  

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Ann sleeps 8 hours a night. write an expression for the number of hours Ann sleeps in n nights
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It's 8n meaning 8 times n (8*n) so for example for 5 nights she would sleep : 8*5 = 40 hours in total.
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How many ways can 15 people be chosen from a group of 22
anzhelika [568]

Answer:

170544\text{ ways}

Step-by-step explanation:

If we don't care about the order (like if we pick Bob then Joe vs Joe then Bob), then a formula is \frac{n!}k!{(n-k)!} where we are picking k items from a list of n items

In our case, n=22 and k=15

Therefore, there are \frac{22!}{15!(22-15)!}=

\frac{22*21*20*19*18*17*16}{(7)!}=

\frac{22*21*20*19*18*17*16}{7*6*5*4*3*2*1}=

\frac{2*11*7*3*5*4*19*6*3*17*16}{7*6*5*4*3*2*1}=

11*19*3*17*16=

170544\text{ ways}

6 0
3 years ago
Suppose a polling agency reported that 44.4​% of registered voters were in favor of raising income taxes to pay down the nationa
g100num [7]

Answer:

<em>95% of confidence interval for the proportion of registered voters who are in favor of raising income taxes to pay down the national debt.</em>

<em>(0.414 ,0.474)</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

<em>Given sample proportion </em>

<em>                                     p⁻ = 44.4 % = 0.444</em>

<em>Random sample size 'n' = 1049</em>

<em>Given margin of error for 95% confidence level = 3 % = 0.03</em>

<u><em>Step(ii):-</em></u>

<em>95% of confidence interval for the proportion is determined by</em>

(p^{-} - Z_{\alpha }\sqrt{\frac{p^{-} (1-p^{-} }{n} }  , p^{-} + Z_{\alpha }\sqrt{\frac{p^{-} (1-p^{-} }{n} })<em></em>

we know that

<em>Margin of error for 95% confidence level is determined by</em>

M.E = Z_{\alpha }\sqrt{\frac{p^{-} (1-p^{-}) }{n} }

<u><em>Step(iii):-</em></u>

Now

<em> 95% of confidence interval for the proportion is determined by</em>

(p^{-} - M.E, p^{-} + M.E)<em></em>

<em>Given Margin of error </em>

<em>                               M.E = 0.03</em>

<em>Now 95% of confidence interval for the proportion</em>

(0.444 - 0.03, 0.444+ 0.03)<em></em>

<em>(0.414 ,0.474)</em>

<u><em>Conclusion:-</em></u>

<em>95% of confidence interval for the proportion of registered voters who are in favor of raising income taxes to pay down the national debt.</em>

<em>(0.414 ,0.474)</em>

6 0
3 years ago
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