Answer:
50
Step-by-step explanation:
Given:
A space shuttle can travel at 28968 km/h.
To find:
The distance it can cover in 8 hrs.
Solution:
We have,
Speed of space shuttle = 28968 km/h.
So,
Distance covered by the space shuttle in 1 hour = 28968 km/h.
Distance covered by the space shuttle in 8 hour = (28968 × 8) km
= 231744 km
Therefore, the distance it can cover in 8 hrs is 231744 km.
A^2 + b^2 = c^2
8^2 + b^2 = 11^2
64 + b^2 = 121
b^2 = 121 - 64
b^2 = 57
b = sqrt 57
b = 7.54 rounds to 7.5 ft <==
Answer:
No solution
Step-by-step explanation:
18x - 5 < 3(6x - 2) Distribute the 3 to (6x - 2)
18x - 5 < 18x - 6
-18x -18x Subtract 18x from both sides
-5 < -6 There is no solution because -5 is not less than -6.
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