Question

Pls someone help I need this urgently done

Answer 1

Answer:

$p=3$ and $q=4$ the mistake was in calculating $3q-4q-10=6$ let's solve first.

Step-by-step explanation:

if $p= 2q-5$, substitute the $p$ in the equation$3q-2p=6$ as

$3q-2(2q-5)=6$

solve the equation in parentheses :

$3q-2(2q-5)$

multiply  $-2$ by $(2q-5)$ it will equal to:  $3q-4q+10$

now we want to let all unknown digits alone, so we will take $10$ to the other side with a different sign it will be as:

$3q-4q=6-10$

now we will solve it:

$3q-4q=6-10\\q=-4$ at this part, the given equation was wrong in the paper.

we don't want the digit to be negative so we will do it like this:

$\frac{-q}{-1} =\frac{-4}{-1 } = q=4$

now that we found $q$ we will substitute it to find $p$:

$p=2q-5\\q=4\\p=2(4)-5\\p=8-5\\p=3$

overall the mistake was in calculating $q$ instead of putting $3q-4q=6-10$  

he/she put a different sign in front of the digit like :$3q-4q-10=6$

so when he/she flipped  $-10$ it became positive and instead of subtracting he/she added it.