Answer:
4) 81/16
Step-by-step explanation:
Just solve the equation,
{3^2.5^0/4}^2
(9×1/4)^2
(81/16)
Hope it helps!
3x + 2y = 10 .....multiply by -2
2x + 3y = 15/2...multiply by 3
------------------
-6x - 4y = -20 (result of multiplying by -2)
6x + 9y = 22.5 (result of multiplying by 3)
-----------------add
5y = 2.5
y = 2.5/5
y = 1/2
3x + 2y = 10
3x + 2(1/2) = 10
3x + 1 = 10
3x = 10 - 1
3x = 9
x = 9/3
x = 3
solution is (3,-1/2)
X²(x - 4) +4 (x - 4)
(x² + 4) (x - 4)
First find the common terms that can enter into both x³ and 4x² then write its down in this case it’s x² that can enter x³ leaving only x _since x³/x² = subtract of the indices. x² will also enter 4x² leaving only four hence you having x² (x - 4)
then do the same for the next pair of terms giving you 4 that can enter into both 4 and 16
Leaving you with +4 (x - 4)
Now you can put the common terms together like so (x² + 4) and choose get one of the other two which are the same= (x - 4)
= (x² + 4) (x - 4)
It looks like the next six terms are 22, 26, 30, 34, 38, 42
It is increasing by 4
