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3 years ago

Simplify 2.5x+0.1x-0.01x=

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

6 0

PEMDAS
2.5x + 0.1x = 2.6x
2.6x - 0.01x = 2.59x

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An exam will consist of True-False questions worth 3 points each and short essay questions worth 11 points each. Write an expres

podryga [215]

Answer:

T3+E11

Step-by-step explanation:

I put this on a test and im sorry if im wrong lol.

HOPE I HELPED.

if i did maybe i can get brainlist. :)

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3 years ago

Read 2 more answers

Find an equation of the line passing through the point (−6,−5) that is parallel to the line y=4/3x−5

Zinaida [17]

Answer:

y = $\frac{4}{3}$ x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{4}{3}$ x - 5 ← is in slope- intercept form

with slope m = $\frac{4}{3}$

Parallel lines have equal slopes, thus

y = $\frac{4}{3}$ x + c ← is the partial equation

To find c substitute (- 6, - 5) into the partial equation

- 5 = - 8 + c ⇒ c = - 5 + 8 = 3

y = $\frac{4}{3}$ x + 3 ← equation of parallel line

5 0

3 years ago

There are 12 more apples than oranges in the basket of 36 apples and oranges. How

anygoal [31]

Step-by-step explanation:

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

Total number of fruits=36

Let

the number of oranges =x

The number of apples=x+12

${:}\leadsto$ $\sf x+x+12=36$

${:}\leadsto$ $\sf 2x+12=36$

${:}\leadsto$ $\sf 2x=36-12$

${:}\leadsto$ $\sf 2x=24$

${:}\leadsto$ $\sf x={\dfrac {24}{2}}$

${:}\leadsto$ $\sf x=12$

Number of Apples =12+12=24

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3 years ago

Read 2 more answers

A bag contain 3 black balls and 2 white balls.

Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

$Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\$

$Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}$

Probability of at least one black( means BB or BW or WB)

$=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}$

Probability of at most one black ( means WW or WB or BW)

$=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}$

a) Probability both black without replacement

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

b) Probability of one black and one white

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

c) Probability of at least one black ( BB or BW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}$

d) Probability of at most one black ( BW or WW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}$

6 0

3 years ago

A student earned grades of B, B, A, C, and D. Those courses had these corresponding numbers of credit hours: 4, 5, 1, 5, 4.

antiseptic1488 [7]

Answer:

Step-by-step explanation:

Let the five courses with their corresponding credit hours be represented as shown;

FST 201 = 4

FST 203 = 5

FST 112 = 1

FST 219 = 5

FST 223 = 4

If a student earned grades of B, B, A, C, and D respectively in those courses with the following grading system A =4, B =3, C =2, D =1, and F =0, before we can get the student GPA, we need to know the total credit point for the five courses.

Credit point for each course = Number of credit hour * point for each grade

FST 201 = 4 * 4 = 16points (A)

FST 203 = 5 * 4 = 20points (A)

FST 112 = 1 * 4 = 4points (A)

FST 219 = 5 * 4 = 20points (A)

FST 223 = 4 * 4 = 16points (A)

Total credit point = 16+20+4+20+16 = 76points

Total credit point gotten by the student is calculated as thus;

FST 201 = 4 * 3 = 12points (B)

FST 203 = 5 * 3 = 15points (B)

FST 112 = 1 * 4 = 4points (A)

FST 219 = 5 * 2 = 10points (C)

FST 223 = 4 * 1 = 4points (D)

Total credit point gotten by the student = 45points.

student's Grade Point Average (GPA) = Total credit point/Total credit point gotten by the student = 76/45 = 1.69 (to 2dp)

5 0

3 years ago