Answer:
B (Y, N, N)
Step-by-step explanation:
a) y = 1/3x, so each value satisfies it. This is true.
b) If "a" is "Y" then b has to be no
c) 1 * 11 = 11
2 * 2 = 22
3 * 5 = 15
The last equation does not follow the rules for the previous two equations, so it is no.
Thus, the answer is B (Y, N, N)
Answer:
The number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Step-by-step explanation:
The question is:
If my hard drive has a capacity of 1.5 Terabytes, how many 32 Gigabit keys can fit on that hard drive?
Solution:
1 Terabyte = 8000 Gigabits
Then 1.5 Terabytes in Gigabits is:
1.5 Terabytes = (8000 × 1.5) Gigabits
= 12000 Gigabits
One key is of 32 Gigabits.
Compute the number of 32 Gigabit keys that can be fitted on the hard drive as follows:

Thus, the number of 32 Gigabit keys that can be fitted on the hard drive is 375.
Set f(b) = b^2 - 75 = to 0 and solve for b:
b^2 = 75
b^2 = 25(3)
b = plus or minus sqrt(25[3]) = plus or minus sqrt(25)*sqrt(3) = plus or minus 5 sqrt(3).
Answer:
1 g/cm³
Step-by-step explanation:
Volume of the model:
V=1/3bh= 1/3*100*6= 300 cm³
Density= weight/volume= 300 g/300 cm³= 1 g/cm³
The lowest density is 1 g/cm³
Answer:
51 students.
Step-by-step explanation:
First you need to establish a rate 6/100+3/50
8*100=800 6*8=48
3/50
850-800=50 3/50
48+3=51