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IgorC [24]
3 years ago
10

What is 6/7 as a decimal

Mathematics
2 answers:
bonufazy [111]3 years ago
8 0
6/7 is approximately equal to 0.857 in decimal form
Klio2033 [76]3 years ago
7 0
0.86 if it is rounded.
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What is the square roots of 9
Lyrx [107]

Answer:

(x-3) and (x+3) I think

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In triangle QRS, QR = 8 and RS = 5. Which expresses all possible length of side QS?
VLD [36.1K]
Obviously it's answer D) Why?

a) any side of a triangle is SMALLER than the SUM of the 2 others

b) any side of a triangle is GREATER than the DIFFERENCE of the 2 others

Hence D) 8-5 < QS < 8+5==>3 < QS < 13
8 0
3 years ago
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PLEASE HELP ME ON THIS AND SHOW UR WORK<br> THX
swat32
When an exponential function is given as 
f(x)=ab^x, and
knowing that b^0=1, that means that
f(0)=ab^0=a  value of function when x=0, or the initial value.
In the case of
f(x)=20.b^x, f(0)=20.b^0 = 20  (initial value)

If b=1.2, then the hourly growth rate is (1.2-1)=0.2=20%.
If b=1.85, then the hourly growth rate is (1.85-1)=0.85=85%. 
4 0
3 years ago
The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp
beks73 [17]

Answer:

(5.4582 ; 6.8618)

Step-by-step explanation:

Given the data:

6 10 2 6 3 3 3 6 6 6 6 5 8 9 10 10 7 9 3 6 5 10 9 9 10 3 8 6 6 3 3 6 6 5 4 10 9 3 5 7 10 6 3 8 6 8 3 3 5 5

Sample mean, xbar = Σx / n

n = sample size = 50

ΣX = 308

xbar = 308 / 50 = 6.16

Using a Calculator :

The sample standard deviation, s = 2.469

Confidence interval = xbar ± margin of error

Margin of Error = Tcritical * s/sqrt(n)

Tcritical at 95% ; df = 50 - 1 = 49

Tcritical = 2.010

Hence,

Margin of Error= 2.010 * (2.469/sqrt(50)) = 0.7018

Lower boundary : (6.16 - 0.7018) = 5.4582

Upper boundary : (6.16 + 0.7018) = 6.8618

(5.4582 ; 6.8618)

4 0
2 years ago
G. Write the equation of the line in slope-intercept form.
Neko [114]

Answer:

  • y= x-2
  • y = 4/5 x+39/5

Step-by-step explanation:

1.

(3,1) and\:perpendicular \:to \: y = -x+1\\(3,1) = (x,y)\\m = -1\\In\: perpendicularism ; m_2 = \frac{-1}{m_1} \\m_2 = \frac{-1}{-1} \\m_2 =1\\y = mx+c\\1 = 1(3) +c\\1=3+c\\1-3=c\\-2 =c\\Substitute \:new \:values\:into\\y =mx+c\\y = 1x -2\\y = x-2

2.

(-1,7) =(x_1,y_1)\\\\5y = 4x+5\\\\Write\:in\:y=mx+c\:form\\\frac{5y}{5} = \frac{4}{5} x + \frac{5}{5} \\y = \frac{4}{5} x +1\\m = \frac{4}{5} \\\\y -y_1=m(x-x_1)\\y-7=\frac{4}{5} (x -(-1)\\y -7 = 4/5(x+1)\\y -7 = 4/5x +4/5\\\\y = \frac{4}{5} x+\frac{4}{5} +7\\\\y = \frac{4}{5} x +39/5

6 0
3 years ago
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