Answer:
Step-by-step explanation:
We are given that a and b are rational numbers where
and x is irrational number .
We have to prove a+bx is irrational number by contradiction.
Supposition:let a+bx is a rational number then it can be written in
form
where
where p and q are integers.
Proof:
After dividing p and q by common factor except 1 then we get

r and s are coprime therefore, there is no common factor of r and s except 1.
where r and s are integers.


When we subtract one rational from other rational number then we get again a rational number and we divide one rational by other rational number then we get quotient number which is also rational.
Therefore, the number on the right hand of equal to is rational number but x is a irrational number .A rational number is not equal to an irrational number .Therefore, it is contradict by taking a+bx is a rational number .Hence, a+bx is an irrational number.
Conclusion: a+bx is an irrational number.
Answer:
y=-100x+700
Step-by-step explanation:
Slope=Rise/Run=Δy/Δx=(y₂-y1)/(x₂-x₁)=(200-600)/(5-1)=(-400)/(4)=-100
So your slope would be m=-100
To find b, the y-intercept, we plug in a given output of y for a given input of x and solve for b:
y=mx+b (Slope-intercept form)
y=-100x+b (Equation so far)
200=-100(5)+b [Plugging in (5,200)]
200=-500+b
700=b
So since the y-intercept is b=700, then the equation of the line is y=-100x+700
Answer: 5.8% = 0.058 in decimal form.
Step-by-step explanation:
Answer:
Identity property of addition: The sum of 0 and any number is that number. For example, 0 + 4 = 4 0 + 4 = 4 0+4=40, plus, 4, equals, 4.
Step-by-step explanation: