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disa [49]
4 years ago
5

ANSWER PLZZZZZzzzzzzzzzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
Usimov [2.4K]4 years ago
5 0
X is your answer I think
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(10x^3y^-2/5x^-3y^4)^-3, x≠0, y≠0
zhenek [66]

Answer:

  \dfrac{y^{18}}{8x^{18}}

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

  (a^b)^c = a^(bc)

__

Your expression simplifies as follows:

  \left(\dfrac{10x^3y^{-2}}{5x^{-3}y^4}\right)^{-3}=(2x^{3-(-3)}y^{-2-4})^{-3}=(2x^6y^{-6})^{-3}\\\\=(2^{-3})x^{6(-3)}y^{(-6)(-3)}=\dfrac{1}{8}x^{-18}y^{18}\\\\=\boxed{\dfrac{y^{18}}{8x^{18}}}

6 0
4 years ago
Find the equation of a line passing through the points (3, -1) with the gradient M=2÷3​
Anvisha [2.4K]

Answer:

y = \frac{2}{3} x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = \frac{2}{3}, thus

y = \frac{2}{3} x + c ← is the partial equation

To find c substitute (3, - 1) into the partial equation

- 1 = 2 + c ⇒ c = - 1 - 2 = - 3

y = \frac{2}{3} x - 3 ← equation of line

3 0
3 years ago
A stone is thrown vertically upwards with an initial velocity 20m/s. Find the maximum height it reaches and the time taken by it
Gemiola [76]

Answer:

The maximum height it reaches is 20 meters

The time taken by it to reach the height is 2 seconds

Step-by-step explanation:

The formula of the height of the stone is h = u t - \frac{1}{2} g t², where

  • t is the time to reach the height h
  • u is the initial velocity
  • g is the acceleration of gravity

∵ A stone is thrown vertically upwards with an initial velocity of 20 m/s

∴ u = 20 m/s

∵ g = 10 m/s²

→ Substitute them in the equation above

∴ h(t) = 20t - \frac{1}{2} (10) t²

∴ h(t) = 20t - 5t²

→ Arrange the terms of the right side according to the greatest power of t

∴ h(t) = -5t² + 20t

To find the maximum height and the time of it find the vertex of the quadratic function (m, k), where m = \frac{-b}{2a} and k is the value of h at t = m, a is the coefficient of t² and b is the coefficient of t

∵ The coefficient of t² is -5

∴ a = -5

∵ The coefficient of t is 20

∴ b = 20

→ Use them to find h

∵ m = \frac{-20}{2(-5)} = \frac{-20}{-10} = h

∴ m = 2

→ Substitute it in the equation above to find k

∵ h(m) = k

∵ k = -5(2)² + 20(2)

∴ k = -5(4) + 40

∴ k = -20 + 40

∴ k = 20

∴ The coordinate of the vertex of the function are (2, 20)

→ m represents the time of the maximum height and k represents

  the maximum height

∴ The maximum height it reaches is 20 meters

∴ The time taken by it to reach the height is 2 seconds

5 0
3 years ago
If a = { 1,2,3,...,10} and U={1,2,4,8} then find A'​
yuradex [85]

Answer:

U-A empty

Step-by-step explanation:

all in a is in u in u is in a therfore empty is found on u but not in a

4 0
2 years ago
Write the following algebraically, using x as your unknown.
Vinvika [58]

Answer:

4(2x - 3).

Step-by-step explanation:

(x * 2 - 3) * 4

= 4(2x - 3)

5 0
3 years ago
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