Question

Which rule describes the composition of transformations that maps ΔBCD to ΔB"C"D"?

Answer 1

Answer:

1. a reflection across the y-axis.
2. a reflection across the line y = x.

Step-by-step explanation:

In the image attached you can oberve that the order of tranformations is

$\triangle BCD \implies \triangle B'C'D' \implies \triangle B''C''D''$

The first transformation $\triangle BCD \implies \triangle B'C'D'$ is a reflection across the y-axis, notice that this axis works as a mirror, that indicates such reflection. Also, when this reflection is applied, all x-values in all cordinates change to the opposite, in this case, from positive to negative. For example, C(1,2) changed to C'(-1,2)

The second transformation $\triangle B'C'D' \implies \triangle B''C''D''$ is a reflection across the line y = x, that is, across the origin of the coordinate system which is at (0,0). One way to notice this transformation is observing the coordinates, they change of place, for example B'(-1, 4) changed to B''(4, -1)

Therefore, the transformations are:

1. a reflection across the y-axis.
2. a reflection across the line y = x.

Answer 2

Answer:

Which rule describes the composition of transformations that maps ΔBCD to ΔB"C"D"?

C. is the answer

Translation of 5 units x, negative 6 units y composition reflection across y = negative x

Reflection across y = negative x composition translation of 5 units x, negative 6 units y.

Translation of 6 units x, negative 5 units y composition reflection across the y-axis

Reflection across the y-axis composition translation of 6 units x, negative 5 units y

Step-by-step explanation:

Took the test.