keeping in mind that the points are A(-8 , 6) and C(2 , 5), so
![\textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-8}~,~\stackrel{y_1}{6})\qquad C(\stackrel{x_2}{2}~,~\stackrel{y_2}{5})~\hspace{8em} \frac{2}{5}\textit{ of the way from A to C} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{2}-\stackrel{x_1}{(-8)}~~,~~ \stackrel{y_2}{5}-\stackrel{y_1}{6})\qquad \implies \qquad \stackrel{\stackrel{\textit{component form of}}{\textit{segment AC}}}{\left( 10 ~~,~~ -1 \right)} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Binternal%20division%20of%20a%20segment%20using%20a%20fraction%7D%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B-8%7D~%2C~%5Cstackrel%7By_1%7D%7B6%7D%29%5Cqquad%20C%28%5Cstackrel%7Bx_2%7D%7B2%7D~%2C~%5Cstackrel%7By_2%7D%7B5%7D%29~%5Chspace%7B8em%7D%20%5Cfrac%7B2%7D%7B5%7D%5Ctextit%7B%20of%20the%20way%20from%20A%20to%20C%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_2%7D%7B2%7D-%5Cstackrel%7Bx_1%7D%7B%28-8%29%7D~~%2C~~%20%5Cstackrel%7By_2%7D%7B5%7D-%5Cstackrel%7By_1%7D%7B6%7D%29%5Cqquad%20%5Cimplies%20%5Cqquad%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bcomponent%20form%20of%7D%7D%7B%5Ctextit%7Bsegment%20AC%7D%7D%7D%7B%5Cleft%28%2010%20~~%2C~~%20-1%20%5Cright%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\left( \stackrel{x_1}{-8}~~+~~\frac{2}{5}(10)~~,~~\stackrel{y_1}{6}~~+~~\frac{2}{5}(-1) \right)\implies \left(-8+4~~,~~6-\frac{2}{5} \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill B\left(-4~~,~~5\frac{3}{5} \right)~\hfill](https://tex.z-dn.net/?f=%5Cleft%28%20%5Cstackrel%7Bx_1%7D%7B-8%7D~~%2B~~%5Cfrac%7B2%7D%7B5%7D%2810%29~~%2C~~%5Cstackrel%7By_1%7D%7B6%7D~~%2B~~%5Cfrac%7B2%7D%7B5%7D%28-1%29%20%5Cright%29%5Cimplies%20%5Cleft%28-8%2B4~~%2C~~6-%5Cfrac%7B2%7D%7B5%7D%20%5Cright%29%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20B%5Cleft%28-4~~%2C~~5%5Cfrac%7B3%7D%7B5%7D%20%5Cright%29~%5Chfill)
This question is incomplete because it lacks the appropriate diagram.
Please find attached to this answer , the appropriate diagram
Answer:
First option tan x° = 8 ÷6
Step-by-step explanation:
When we solve for angles in a right angled triangle or we are trying to find one if the sides of a right angled triangle, we used trigonometric functions to find our answers. These trigonometric functions include Sine (sin) , Cosine (cos) and Tangent (tan)
Tangent also called short form tan is used when solving problems involving a right angled triangle.
A right angled triangle has 3 sides, the Hypotenuse, the opposite side and the adjacent side.
When we are asked to find the tangent of an angle,
tan = Opposite side / Adjacent side
In the question above, we are asked to find tan x° where x is the angle.
The opposite side = 8cm
The adjacent side = 6cm
Therefore, tan x° = 8cm/6cm = 8cm ÷ 6cm




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F(x) represents the value of y on curve for given value of x


[ since 0 < 2 ]




[ since 2 = 2 ]




[ since 4 > 2 ]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞
People in building ---- x (men, women and children)
children --- y
men + women + children = x
(3/7)x + (5/8)(4/7)x + y = x
3x/7 + 5x/14 + y = x
times 14
6x + 5x + 14y = 14x
14y = 3x
y + 220 =x
sub into the other one
14y = 3(y+220)
11y = 660
y = 60
then 14(60) = 3x ---> x = 280
So we have 280 people in the building.
check: 3/7 of 280 are men = 120
leaving 160 women and children
5/8 of these ot 100 are women
so we have 120 men, 100 women and 60 children!
hope this is right! have a great. day
Answer:
New cut off salary = 30,592
Step-by-step explanation:
Given:
Normal distributed mean = $37,000
Standard deviation = $5000
Cut off salary = 10%
Find:
New cut off salary
Computation:
Z - left tale value of 10% is -1.2816
Corresponding x-value using x = zs + u
New cut off salary = (-1.2816)(5,000) + 37,000
New cut off salary = -6,408 + 37,000
New cut off salary = 30,592