All categories

2 years ago

Unit 4

Mathematics

1 answer:

Dennis_Churaev [7]2 years ago

6 0

He did this then that plus to this and that =334.2

You might be interested in

The shaded triangle is set inside a pentagon. What type of triangle is the shaded triangle?

SpyIntel [72]

That is a right angled triangle

5 0

3 years ago

Read 2 more answers

Determine whether the graph is the graph of a function. Yes or No

tankabanditka [31]

A function is a rule that relates inputs to outputs.It takes elements from the domain and relates them to the codomain. It relates each element of a set with exactly one element of another set. In the graph, we see a single element of a set being mapped to different codomain. Thus, the graph does not represent a function

6 0

3 years ago

You can model the entrance to a mine shaft using the equation

Furkat [3]

y=-1/2 2 (x+4)(x+-4+

-1/2*2 = -1

y=-1(x+4)(x-4)

solving for x

x - -4 and x =4

-4 to 4 = 8 feet

width = 8 feet

4 0

3 years ago

Read 2 more answers

How do you decide which of two numbers is greater when one number is positive and one number is negative

Degger [83]

Positive numbers are always greater than negative numbers

8 0

3 years ago

Read 2 more answers

A backyard pool has a concrete walkway around it that is 3 feet wide on all sides. The total area of the pool and the walkway is

Gnoma [55]

Answer:

<h2>29.4 length and 21.4 width.</h2>

Step-by-step explanation:

To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that W is the width and L the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this: $A_{total} = (L+6)(W+6)$ .

In addition, we know that the total area is 970 and the length is 8 ft longer than the width ( $L=W+8$ ). So:

$A_{total} = (L+6)(W+6)\\970 = (W+8+6)(W+6)\\970=W^{2}+20W+84\\W^{2}+20W-886=0$

With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions: $W_{1}=21.4$ and $W_{2}=-41.4$

Therefore, the width is 21.4 ft, because the negative number cannot represent distances.

Using the relation between length and width:

$L=W+8\\L=21.4+8=29.4$

Therefore, the dimensions of the pool are 29.4 length and 21.4 width.

7 0

3 years ago