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s344n2d4d5 [400]
3 years ago
9

Select all of the choices that are equal to (-5) – (-12).

Mathematics
2 answers:
krek1111 [17]3 years ago
4 0
The answer is 7 i’m pretty sure
ohaa [14]3 years ago
4 0
2 and 5 are both equal to (-5)-(-12)
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Which statement describe the decimal equivalent of 3/8
Darina [25.2K]

Answer:

Hi! The answer to your question is 0.375

Step-by-step explanation:

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3 years ago
6.2megagrams/hectoliter to kilograms/deciliter
lesya [120]

Answer:

6.2 kilograms/ deciliters

Step-by-step explanation:

megagrams to kilograms

1 megagram = 1000 kilograms

hectoliter to deciliter

1 hectoliter = 1000 deciliter

Using conversion factors

6.2megagrams      1000 kilgrams         1 hectoliter

---------------------- * ----------------------- * -------------------------

hectoliter                  1 megagram       1000 deciliters

Canceling like terms

6.2 kilograms/ deciliters

6 0
3 years ago
Read 2 more answers
What is 64 x 51.64 / x?
Bumek [7]
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3 0
3 years ago
Report Error Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\
motikmotik

Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in \sqrt{7}, 1 - \sqrt{6} and -3. The last root gives us the factor (x+3). Hence, our polynomial is

P(x) =(x+3)q(x)

where q is a polynomial with rational coefficients and roots \sqrt{7} and 1 - \sqrt{6}. The root \sqrt{7} gives us a factor x-\sqrt{7}, but in order to obtain rational coefficients we must consider the factor x^2-7.

An analogue idea works with 1 - \sqrt{6}. For convenience write  x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}. This gives the factor (x-1)^2-6. Hence,

P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105

Notice that P(-1)=24. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type x-\sqrt7 will introduce in the expression, we need to multiply by its conjugate x+\sqrt7. Hence, we will obtain x^2-7 that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.

4 0
3 years ago
4.5+16.02 work and answer
lbvjy [14]

Answer: 20.52

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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