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3 years ago

Find the sum to infinity

Mathematics

1 answer:

boyakko [2]3 years ago

6 0

Answer:

-7/27

Step-by-step explanation:

-14/54

Hope this helped :)

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Given that y l b and z l b what conclusion can be made

Helen [10]

Answer:

y I z

Step-by-step explanation:

We can see that y I b and z I b we can conclude also that

y I z.

3 0

3 years ago

The value of (a-1)+a^2-b^2/1-ab+2(a-b)/2b when a=2 and b=-1 is ?

poizon [28]

<span>The value of (a-1)+a^2-b^2/1-ab+2(a-b)/2b when a=2 and b=-1 will be evaluated as follows:
substituting the values in the expression we obtain:
(2-1)+2^2-(-1)^2/1-(2*(-1))+2(2-(-1))/(2(-1))
simplifying the above we get:
1+4-1/1-(-2)+2(2+1)/(-2)
=1+4-1+2(3)/(-2)
=1+4-1-3
=5-4
=1

Answer: 1</span>

8 0

3 years ago

Find the coordinates of the midpoint of AB given A (2,3) and B (4, -2)

marshall27 [118]

Answer:

(3, 1/2)

Step-by-step explanation:

The x-coordinate of the midpoint of AB is the arithmetic mean of 2 and 4, which comes out to 3. The y-coordinate of the midpoint of AB is the arithmetic mean of 3 and -2, which comes out to 1/2.

Thus the midpoint of AB is (3, 1/2).

8 0

3 years ago

Hw 28 shades figure

ra1l [238]

Answer:

Prat 9) $SF=2, x=16\ in$

Part 10) $SF=0.5, x=14\ ft$

Part 11) $SF=0.5, x=3.5\ ft$

Part 12) $SF=3, x=7\ m$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

SF-----> the scale factor

a----> area of the shaded figure

b----> area of the unshaded figure

$SF^{2} =\frac{x}{y}$

Problem 9) we have

$a=216\ in^{2}$

$b=54\ in^{2}$

substitute in the formula

$SF^{2}=\frac{216}{54}$

$SF^{2}=4$

$SF=2$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(2)(8)=16\ in$

Problem 10) we have

$a=161\ ft^{2}$

$b=644\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{161}{644}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(28)=14\ ft$

Problem 11) we have

$a=10.5\ ft^{2}$

$b=42\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{10.5}{42}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(7)=3.5\ ft$

Problem 12) we have

$a=4,590\ m^{2}$

$b=510\ m^{2}$

substitute in the formula

$SF^{2}=\frac{4,590}{510}$

$SF^{2}=9$

$SF=3$ ------> the scale factor

To find the value of x, divide the length of the shaded figure by the scale factor

$x=(21)/(3)=7\ m$

4 0

4 years ago

PLEASE PLEASE PLEASE HELP!!

ELEN [110]

Answer:

Step-by-step explanation:

Well first you have to find the dimensions of the frame, you can find that by subtracting the dimensions of the photo from the whole dimensions so it will be the

length of the photo and frame - length of the photo = 25- 20 = 5 length of the frame

Now the width of the photo and frame - width of the photo = 20 -16 = 4 the width of the frame

ok so the Area of the rectangle = width x length = 4 x 5 = 20 the Area of the frame

Hope that helps

6 0

3 years ago

Find the sum to infinity​

Find the sum to infinity