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Zepler [3.9K]
3 years ago
12

IN A CLASS OF 100 57 STUDENTS RECEIVED A GRADE A WHAT FRACTION DID NOT RECEIVE AN A

Mathematics
2 answers:
AysviL [449]3 years ago
4 0
57/100 of students did not recieve an A

dexar [7]3 years ago
3 0
43/100 did not receive an 'A'. There is no proper way to simplify.
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Decrease 117 kg in the ratio 10:13​
Lisa [10]

Answer:

90kg

Step-by-step explanation:

it is so because, to decrease a number by a ratio you have to multiply with the smallest number and divide with the biggest one. For example 117 in the ratio 7:3. 117×3=351 which is divided by 7 and is equal to 50.14.

8 0
2 years ago
how many pounds of nuts selling for $9 per lb and raisins selling for $3 per lb should a person combine to obtain 60 lb of a tra
marta [7]
Let n be the number of lbs of nuts.
Let r be the number of lbs of raisins.
9n + 3r = 60 * 5 = 300 .............(1)
n + r = 60
n = 60 - r ...............(2)
Plugging the expression for n in (2) into (1) we get:
9(60 - r) + 3r = 300
which expands to:
540 - 9r + 3r = 300 .............(3)
Simplifying and rearranging (3) we get:
-6r = -240
Therefore r, the weight of raisins = 40 lbs
and the weight of nuts is 60 - 40 = 20 lbs
8 0
3 years ago
How many kilograms of lentils will each person get if 3 people share 1/5 of a kilogram of lentils equally?
AysviL [449]

Answer:

1/15 of a kilogram

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If the area of the trapezoid shown is 200 square feet, what is the height h of the trapezoid?
r-ruslan [8.4K]

Answer:

hope this helps u!

Step-by-step explanation:

8 0
2 years ago
Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet
Irina18 [472]

The distance from Ship B to the signal fire at point C is 405.4 \mathrm{ft}

Explanation:

It is given that two ships A and B are at a distance 140 ft from each other.

The angle formed by ship A is 82º and the angle formed by ship B is 78º.

To determine the distance from ship B to the signal fire at point C, we need to know the another angle.

Hence, we have,

\begin{aligned}\angle A+\angle B+\angle C &=180^{\circ} \\82^{\circ}+78^{\circ}+\angle C &=180^{\circ} \\160^{\circ}+\angle C &=180^{\circ} \\\angle C &=20^{\circ}\end{aligned}

Now, we shall solve the problem using the law of sines,

\frac{\sin A}{a}=\frac{\sin C}{c}

Substituting the values, we have,

\frac{\sin 82^{\circ}}{a}=\frac{\sin 20^{\circ}}{140}

\frac{0.9903}{a}=\frac{0.3420}{140}

Simplifying, we get,

a=\frac{0.9903 \times 140}{0.3420}

a=405.4

Thus, the distance from Ship B to the signal fire at point C is 405.4 \mathrm{ft}

4 0
3 years ago
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