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SOVA2 [1]
3 years ago
15

3. Nicholas challenges Rajiv with these instructions for finding his house after basketball practice. Get on the subway at 14th

Street. The subway stops at 23rd, 28th 33rd, 42nd, 51st, 59th 68th, 77th, 86th, and 96th Streets. Get off at the first street you eat to that is divisible by both 3 and 7. How can Rajiv solve this problem? At which stop should I get off the subway?
Mathematics
1 answer:
saul85 [17]3 years ago
3 0

Answer:

Rajiv can solve this problem verifying if each street is divisible by both 3 and 7.

You should get off the subway at the 42nd street.

Step-by-step explanation:

Rajiv can solve this problem verifying if each street is divisible by both 3 and 7.

23rd street

23 is not divisible by 3, since 23/3 is not an integer value.

23 is not divisible by 7, since 23/7 is not an integer value.

28th street

28 is not divisible by 3, since 28/3 is not an integer value.

28 is divisible by 7, since 28/7 = 4.

33rd street

33 is divisible by 3, since 33/3 = 11.

33 is not divisible by 7, since 33/7 is not an integer value.

42nd street

42 is divisible by 3, since 42/3 = 14.

42 is divisible by 7, since 42/7 = 6.

You should get off the subway at the 42nd street.

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