A stick is broken into two pieces, at a uniformly random break point. Find the CDF and average of the length of the longer piece .
1 answer:
Answer:
P(L ≤ l) =P (1-l ≤ U ≤ l)= l- ( 1 - l ) = 2 l - 1
Step-by-step explanation:
let assume that stick has length 1.Random variable L that make length of a longer piece and random variable U that mark point .See that L < l means that
U≤ l and 1-U ≤l
P(L ≤ l) =P (1-l ≤ U ≤ l)= l- ( 1 - l ) = 2 l - 1
this means 1-l≤U≤l
so we have
if we have L [1/2,1]
then apply the formula we have E(L)=3/4
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