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3 years ago

What lists all integer solutions of the inequality |x|<2

Mathematics

1 answer:

Nookie1986 [14]3 years ago

4 0

Answer:

The solution to that inequality is (-2,2).

Step-by-step explanation:

Given the inequality |x|<2, we have two possibilities

1) x<2 or

2) -x<2 ⇒ x> -2.

Then the intersection between solutions is (-2, 2).

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Lunna [17]

Answer: X=1.5

Step-by-step explanation:

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3 years ago

What is the equation of a circle with the same center but a radius that is twice as long ?

yaroslaw [1]

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3 years ago

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Hatshy [7]

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Step-by-step explanation:

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3 years ago

A store marks up the price of a sweater by $7.35. The total cost of the sweater is 25.65. How much does the store pay for the sw

UNO [17]

Answer: the store paid $18.3 for the sweater

Step-by-step explanation:

Let x represent the amount that the store paid for the sweater.

A store marks up the price of a sweater by $7.35. This means that the new or current price of the sweater at the store would be

7.35 + x

The total cost of the sweater is 25.65. Therefore, an equation to represent the problem would be

7.35 + x = 25.65

Subtracting 7.35 from the left hand side and the right hand side of the equation, it becomes

7.35 + x - 7.35 = 25.65 - 7.35

x = $18.3

3 0

3 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

8 0

3 years ago