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Effectus [21]
2 years ago
13

Write this expression as a single number. 3^2+3+3^0+3^-1=

Mathematics
2 answers:
andreev551 [17]2 years ago
6 0
40 over 3 is the right one
EastWind [94]2 years ago
5 0
40 over 3

But heres an alternate answer: 13
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What is the interquartile range of 45,60,40,90,60,50,75,120,90
puteri [66]
IQR = 40

1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.

We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.

40, 45, 50, 60, 60, 75, 90, 90, 120

Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;

IQR = 90 - 50 = 40



5 0
3 years ago
What makes an equation false?
stellarik [79]

Answer:

When ever you can’t solve it it considered false like 4 - 12

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Are the 2 triangles congruent? ​
ivann1987 [24]

Answer:

Yes

Step-by-step explanation:

They are just in the opposite side

5 0
3 years ago
The perimeter of a parallelogram is 72 meters. The width of the parallelogram is 4 meters less than its length. Find the length
mafiozo [28]
Perimeter of a parallelogram = 2(l + w). But w = l - 4
Therefore, 72 = 2(l + l - 4) = 2(2l - 4) = 4l - 8
4l = 72 + 8 = 80
l = 80/4 = 20
w = 20 - 4 = 16

Therefore, length = 20 meters and width = 16 meters
7 0
3 years ago
How would you prove this using a flow chart?
Genrish500 [490]

\triangle BCA\sim\triangle DEA\ (AA)\\\text{therefore the ratios of the lengths of their corresponding sides are equal}\\\\\dfrac{BC}{AC}=\dfrac{DE}{AE}\ \ \ |\text{cross multiply}\\\\BC\cdot AE=AC\cdot DE\ \ \ \ |:BC\\\\AE=\dfrac{AC\cdot DE}{BC}\ \ \ \ |:AC\\\\\dfrac{AE}{AC}=\dfrac{DE}{BC}\to\dfrac{DE}{BC}=\dfrac{AE}{AC}

6 0
3 years ago
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